feasible and non feasible solution of lpp

A set of values of the variables x 1 , x 2 , x 3 ,.,x n which satisfy all the constraints and also the non-negativity conditions is called the feasible solution of the LPP..

Graphical Method of Solution of a Linear Programming Problem - So far we have learnt how to construct a mathematical model for a linear programming problem. If we can find the values of the decision variables x 1 , x 2 , x 3 , ..... x n , which can optimise (maximize or minimize) the obje..

Since the reduction potential of Br 2 is more than that of I 2 , it means that bromine can be readily reduced. Therefore, I - will be oxidized to I 2 and this reaction should be written as oxidation. Therefore, the following reactions will occur: Since for the feasibility of the rea..

The graphical method is applicable to solve the LPP involving two decision variables x 1 , and x 2 , we usually take these decision variables as x, y instead of x 1 , x 2 . To solve an LPP , the graphical method includes two major steps. a) The determination of the h..

1 , x 2 , x 3 ,.,x n which satisfy all the constraints and also the non-negativity conditions is called the feasible solution of the LPP. Optimal Solution: The feasible solution, which optimises (i.e., maximizes or mini..

We may come across LPP which may have no feasible (infeasible) solution or may have unbounded solution. We conclude the chapter by giving one example for each of these exceptional cas..

Some Exceptional Cases - We may come across LPP which may have no feasible (infeasible) solution or may have unbounded solution. We conclude the chapter by giving one example for each of these exceptional cas..

Corresponding to each constant, we obtain a shaded region. The intersection of all these shaded regions is the feasible region or feasible solution of the LPP. Let us find the feasible solution for the problem of a decorative item dealer..

Draw the graphs x + y = 1 - 0.5 -5y = - 10 Shade the half planes of the constraints x + y 1 (1) -0.5x - 5y -10 (2) Note that the origin (0, 0) does not satisfy the inequation (2) hence the required region is the upper half plane. From the graph, it is clear that the intersection of the const..

. While one container is filled with a liter of helium gas, the other is filled with a liter of neon gas. The two gases are non-reacting (being inert gases). When the valve is opened, it is observed that the two gases get mixed together spontaneously. During the mixing, there is a negligi..