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Step 1:
Find the feasible region of the LL..
Which of the following is the graph of a linear system of constraints..
Which of the following is the graph of a linear system of constraints? => the feasible region or the constraint region or the linear graph or the linear region..
Which of the following is the graph of a linear system of constraints..
Which of the following is the graph of a linear system of constraints? => The linear graph or The linear region or The feasible region or The constraint region..
Suggested answer:
The intersection of the half planes 2x + y 3 and x - y 0 is shown as shaded region in the figure. Feasible region is an unbounded convex region at A (0, 3), Z = 6 (0) + 3 = 3 At B (1, 1), Z = 6(1) + 1 = 7 Consider any point say (4, 5), the value of Z =..
The intersection of the half planes 2x + y 3 and x - y 0 is shown as shaded region in the figure. Feasible region is an unbounded convex region at A (0, 3), Z = 6 (0) + 3 = 3 At B (1, 1), Z = 6(1) + 1 = 7 Consider any point say (4, 5), the value of Z =..Step 3:
Corresponding to each constant, we obtain a shaded region. The intersection of all these shaded regions is the feasible region or feasible solution of the LPP. Let us find the feasible solution for the problem of a decorative item dealer..
Corresponding to each constant, we obtain a shaded region. The intersection of all these shaded regions is the feasible region or feasible solution of the LPP. Let us find the feasible solution for the problem of a decorative item dealer..Step 4:
To maximise Z draw a line parallel to ax + by = k and farthest from the origin. This line should contain at least one point of the feasible region. Find the coordinates of this point by solving the equations of the lines on which it lies. To minimise Z draw a line parallel to ..
Graphical Method of Solution of a Linear Programming Problem
So far we have learnt how to construct a mathematical model for a linear programming problem. If we can find the values of the decision variables x 1 , x 2 , x 3 , ..... x n , which can optimise (maximize or minimize) the objective function Z, then we say that these values of x i are the ..
Step 2:
+ y 100. Therefore R 1 is the required region for the constraint 2x + y 100. Similarly draw the straight line x + y = 80 by joining the point (0, 80) and (80, 0). Find the required region say R 1 ', for the constraint x + y 80. The intersection of both the region R 1 a..
+ y 100. Therefore R 1 is the required region for the constraint 2x + y 100. Similarly draw the straight line x + y = 80 by joining the point (0, 80) and (80, 0). Find the required region say R 1 ', for the constraint x + y 80. The intersection of both the region R 1 a..Graphical Method of Solution of a Linear Programming Problem
The graphical method is applicable to solve the LPP involving two decision variables x 1 , and x 2 , we usually take these decision variables as x, y instead of x 1 , x 2 . To solve an LPP , the graphical method includes two major steps. a) The determination of the solution space that d..
Basic Concept of Linear Programming Problem
1 , x 2 , x 3 ,.,x n which satisfy all the constraints and also the non-negativity conditions is called the feasible solution of the LPP. Optimal Solution: The feasible solution, which optimises (i.e., maximizes or minimizes as the case may be) the objective function i..
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