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Find the sum of the first 10 terms of the arithmetic series.3x + (4x +..
Find the sum of the first 10 terms of the arithmetic series. 3 x + (4 x + 6 y ) + (5 x + 12 y ) + . . . => 75 x + 270 y or 65 x + 270 y or 270 x + 75 y or 75 x + 260 y..
To find the sum of a number of terms in Arithmetical Progression:
Let a=first term, d = common difference, l=t n =last term, s = required sum. Then, Writing the series in the reverse order, Adding together the two series, ..
Let a=first term, d = common difference, l=t n =last term, s = required sum. Then, Writing the series in the reverse order, Adding together the two series, ..The sum of first n terms of an arithmetic series is 4n2 + 8n, then fin..
The sum of first n terms of an arithmetic series is 4 n 2 + 8 n , then find the common difference. => 8 or 4 or 12 or 28..
Find the common ratio of the geometric series, whose sum of first 39 t..
Find the common ratio of the geometric series, whose sum of first 39 terms, S 39 = 1 0 3 9 - 1 9 . => 9 or 39 or 1 or 10..
In the geometric series r = - 1, S91 = 39. What is the first term?
In the geometric series r = - 1, S 91 = 39. What is the first term? => 0 or 3549 or 39 or - 39..
Write down the first 5 terms of the binomial series for (1 + x)- 3.
Write down the first 5 terms of the binomial series for (1 + x ) - 3 . => IV or III or I or II or V..
In the geometric series r = - 1, S77 = 34. What is the first term?
In the geometric series r = - 1, S 77 = 34. What is the first term? => 0 or 34 or - 34 or 2618..
In the geometric series r = - 1, S71 = 26. What is the first term?
In the geometric series r = - 1, S 71 = 26. What is the first term? => 0 or 1846 or 26 or - 26..
Find the sum to n terms of the series. 4(a - 12) + 16(a2 - 144) + 64(a..
Find the sum to n terms of the series. 4( a - 12) + 16( a 2 - 144) + 64( a 3 - 1728) + ...... => ( 4 a ) ( 1 - ( 4 a ) n ) 1 - 4 a - 4 8 4 7 ( 1 - 4 8 n ) or Cannot be determi..
Find the sum of first n terms of the geometric series.c3, c6, c9, ...
Find the sum of first n terms of the geometric series. c 3 , c 6 , c 9 , ... => n 2 [ 2 c 3 + ( n - 1 ) c 3 ] or c 3 [ 1 - c 3 n ] 1 + c 3 or c 3 [ 1 - c 3 n ] 1 - c 3 or c 3..
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