Converse
"If both pairs of opposite sides of a quadrilateral are equal, then the quadrilateral is a parallelogram". The converse statement stated above is a necessary condition for a quadrilateral to be a parallelogram. Similarly, we may formulate the following two other conditions for a quadrila..
Converse
Any point on the bisectors of one of the angles formed by two intersecting lines is equidistant form the lines..
Any point on the bisectors of one of the angles formed by two intersecting lines is equidistant form the lines..Converse
A transversal intersects two lines. If the alternate angles are equal, then the lines are parallel. If or then AB is parallel to C..
A transversal intersects two lines. If the alternate angles are equal, then the lines are parallel. If or then AB is parallel to C..Calculation
Mass of U-tube with contents before experiment = a grams Mass of U-tube with contents after experiment = b grams Hence, mass of water vapour absorbed = (b - a) g Volume of air = x litres..
Calculations
Let, The mass of the compound taken be = W g Mass of AgX formed = W 1 g From stoichiometry, Ag = X 1 mol 1 mol 1 molecular mass 1 atomic mass Therefore, ..
Let, The mass of the compound taken be = W g Mass of AgX formed = W 1 g From stoichiometry, Ag = X 1 mol 1 mol 1 molecular mass 1 atomic mass Therefore, ..Calculations
Let, The mass of the organic compound taken be = W g Mass of Mg 2 P 2 O 7 obtained = W 1 g From stoichiometry, Mg 2 P 2 O 7 = 2P 1 mol 2 mol 1 x molecular mass 2 x atomic mass 222 g 2 x 31 g = 62 g Therefore, Then, ..
Calculations
Let the mass of platinic chloride salt be = W g The mass of platinum residue left = x g From the molar stoichiometry, Number of mol of B 2 H 2 PtCl 6 = Number of mol of Pt Or If E is the equivalent mass of the organic base, Then molecular mass of the salt (B 2 H 2 PtCl 6 ) = 2E + 2 + 195 + 213 ..
Calculations
Let, The mass of the acid dissolved be = W g Volume of alkali used for complete neutralization of acid solution = V 1 mL Normality of the alkali solution = N 1 Then, we can write, V 1 mL of alkali solution having normality N 1 = Wg acid From the definition, 1000 mL of 1N alkali solution = 1..
Let, The mass of the acid dissolved be = W g Volume of alkali used for complete neutralization of acid solution = V 1 mL Normality of the alkali solution = N 1 Then, we can write, V 1 mL of alkali solution having normality N 1 = Wg acid From the definition, 1000 mL of 1N alkali solution = 1..Calculation
Let, Mass of the organic compound = W g Volume of the standard acid required for complete neutralization of the evolved ammonia = V mL Normality of the standard solution of acid = N From the law of equivalence (normality equation), 1000 mL of 1 N acid = 1000 mL of 1 N NH 3 = 17g NH 3 = 14 g ni..
Let, Mass of the organic compound = W g Volume of the standard acid required for complete neutralization of the evolved ammonia = V mL Normality of the standard solution of acid = N From the law of equivalence (normality equation), 1000 mL of 1 N acid = 1000 mL of 1 N NH 3 = 17g NH 3 = 14 g ni..Converse of a Theorem
Converse of a Theorem is the transposition of a statement consisting of 'data' and 'to prove' 'Data' becomes 'To Prove' and 'To prove' becomes 'Data' in the converse theore..
Result
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