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The general form of the trinomial is (x 2 + cx + d) where c and d have different numerical values: c = a + b, and d = ab. In the given trinomial expression if all terms are positive, then both the factors are positive. If the middle term is negative,..

Trinomials - Expressions of the form ax 2 + bx + c are called trinomialsExpressions of the form ax 2 + bx + c are called trinomials..

Expressions of the form ax 2 + bx + c are called trinomials..

Writing a polynomials as the product of two or more polynomials is called factorisation. If A = B x C, B and C are called factors of A. Methods of Factorisation: (i) Common factors (ii) By expressing as difference of squares (iii) By grouping (iv) Trinomials (v..

Mass of U-tube with contents before experiment = a grams Mass of U-tube with contents after experiment = b grams Hence, mass of water vapour absorbed = (b - a) g Volume of air = x litres..

Let, The mass of the compound taken be = W g Mass of AgX formed = W 1 g From stoichiometry, Ag = X 1 mol 1 mol 1 molecular mass 1 atomic mass Therefore, ..

Let, The mass of the organic compound taken be = W g Mass of Mg 2 P 2 O 7 obtained = W 1 g From stoichiometry, Mg 2 P 2 O 7 = 2P 1 mol 2 mol 1 x molecular mass 2 x atomic mass 222 g 2 x 31 g = 62 g Therefore, Then, ..

Let the mass of platinic chloride salt be = W g The mass of platinum residue left = x g From the molar stoichiometry, Number of mol of B 2 H 2 PtCl 6 = Number of mol of Pt Or If E is the equivalent mass of the organic base, Then molecular mass of the salt (B 2 H 2 PtCl 6 ) = 2E + 2 + 195 + 213 ..

Let, The mass of the acid dissolved be = W g Volume of alkali used for complete neutralization of acid solution = V 1 mL Normality of the alkali solution = N 1 Then, we can write, V 1 mL of alkali solution having normality N 1 = Wg acid From the definition, 1000 mL of 1N alkali solution = 1..

Let, Mass of the organic compound = W g Volume of the standard acid required for complete neutralization of the evolved ammonia = V mL Normality of the standard solution of acid = N From the law of equivalence (normality equation), 1000 mL of 1 N acid = 1000 mL of 1 N NH 3 = 17g NH 3 = 14 g ni..