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Case (i)
C divides AB internally. Let A (x 1 , y 1 ) and B (x 2 , y 2 ) be the two points joined by line segment AB. Let C (x, y) be the point on the line segment such that (In this case, AC and CB are real in the same direction on the line AB.) Draw AP, CR and BQ perpendicular to x-axis. AM..
C divides AB internally. Let A (x 1 , y 1 ) and B (x 2 , y 2 ) be the two points joined by line segment AB. Let C (x, y) be the point on the line segment such that (In this case, AC and CB are real in the same direction on the line AB.) Draw AP, CR and BQ perpendicular to x-axis. AM..Similarity
Introduction - Triangles are similar if they are equiangular and their corresponding sides are proportiona..
Similarity
Similarity - Study the following figures. They have the same shape though their sizes are different. One figure is the enlargement of the other figure. These figures are said to be similar to each other. In our study, we mostly deal with similarity of triangles..
Similarity - Study the following figures. They have the same shape though their sizes are different. One figure is the enlargement of the other figure. These figures are said to be similar to each other. In our study, we mostly deal with similarity of triangles..Similarity Summary
Summary - Enlargement or Dilatation If D PQR is the image of D ABC (Pre image) and K is the enlargement factor, If K = 1 the triangles are congruent. The ratio of their areas is K 2 (SAS similarity) If a pair of corresponding angles are equal and the sides including them are pro..
Summary - Enlargement or Dilatation If D PQR is the image of D ABC (Pre image) and K is the enlargement factor, If K = 1 the triangles are congruent. The ratio of their areas is K 2 (SAS similarity) If a pair of corresponding angles are equal and the sides including them are pro..Similarity Theorem 2 (A.A.) Similarity
Theorem 2 (A.A.) Similarity - If two pairs of corresponding angles are equal, then the triangles are similar. In D ABC and D PQR, A = P and B = Q D ABC ~ D PQR The above theorem may be stated as "If two triangles are equiangular then they are similar..
Theorem 2 (A.A.) Similarity - If two pairs of corresponding angles are equal, then the triangles are similar. In D ABC and D PQR, A = P and B = Q D ABC ~ D PQR The above theorem may be stated as "If two triangles are equiangular then they are similar..Similarity Theorem 4
Theorem 4 - A perpendicular drawn from the right angle vertex of a right - angled triangle divides the triangle into two triangles similar to each other and also to the original triangle. ABC is a triangle right-angled at A. The perpendicu..
Theorem3 (S.S.S) Similarity
If three pairs of corresponding sides are proportional then the two triangles are similar..
Theorem 2 (A.A.) Similarity
If two pairs of corresponding angles are equal, then the triangles are similar. In D ABC and D PQR, A = P and B = Q D ABC ~ D PQR The above theorem may be stated as "If two triangles are equiangular then they are similar..
If two pairs of corresponding angles are equal, then the triangles are similar. In D ABC and D PQR, A = P and B = Q D ABC ~ D PQR The above theorem may be stated as "If two triangles are equiangular then they are similar..Theorem 3 (S.S.S.) Similarity
If three pairs of corresponding sides are proportional then the two triangles are similar. In D ABC and D PQR, D ABC ~ D PQR The above three theorems are without proof. Such theorems can be called postulates. Now, let us compare similar triangles and congruen..
If three pairs of corresponding sides are proportional then the two triangles are similar. In D ABC and D PQR, D ABC ~ D PQR The above three theorems are without proof. Such theorems can be called postulates. Now, let us compare similar triangles and congruen..Triangles - Test Questions
Question 1 - Question: Say whether the following quadrilateral are similar or not. (i) (ii) Answer: (i)ABCD similar to PQRS (ii)ABCD is not similar to PQR..
Question 1 - Question: Say whether the following quadrilateral are similar or not. (i) (ii) Answer: (i)ABCD similar to PQRS (ii)ABCD is not similar to PQR.. Result
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