Units of rate of reaction
. If the concentration of iodine rises from 0 to 10 - 5 mol L - 1 in seconds, [Here symbol D represents a change and I 2 represents the molar concentration of iodine]. This change in concentration of the product (iodine) takes place in ten seconds. Thus the rate can be called th..
. If the concentration of iodine rises from 0 to 10 - 5 mol L - 1 in seconds, [Here symbol D represents a change and I 2 represents the molar concentration of iodine]. This change in concentration of the product (iodine) takes place in ten seconds. Thus the rate can be called th..Action with Acids
Ammonia reacts with the acids to form their respective ammonium salts. ..
Ammonia reacts with the acids to form their respective ammonium salts. ..Solution:
Mass of crystals of Na 2 SO 3 .10H 2 O = 286 Mass of water of crystallisation = 180 Loss of mass = 180 = 62.9..
Mass of crystals of Na 2 SO 3 .10H 2 O = 286 Mass of water of crystallisation = 180 Loss of mass = 180 = 62.9..Problem
10. Why does the temperature of the boiling liquid remains constant even though heating is continued..
Problem
10. Why can't anhydrous magnesium chloride be obtained by heating the hydrated sal..
(g) Bronze
This is an alloy of copper which contains 90% of copper and 10% of tin. It is used in preparation of statue..
Solution:
The given problem is solved in the following table. Empirical formula = N 2 H 8 S 1 O 4 = N 2 H 8 SO 4..
The given problem is solved in the following table. Empirical formula = N 2 H 8 S 1 O 4 = N 2 H 8 SO 4..Action of Alkalis on Solution of Salts
Action of Alkalis on Solution of Salts - Alkalis react with aqueous solutions of salts producing the precipitates of the respective metals as hydroxides. These precipitates are usually colored. From the color and texture of the precipitate, it is possible to identify the metal ions present in the s..
Action of Alkalis on Solution of Salts - Alkalis react with aqueous solutions of salts producing the precipitates of the respective metals as hydroxides. These precipitates are usually colored. From the color and texture of the precipitate, it is possible to identify the metal ions present in the s..Solution:
As per the equation, 2 {39 + 14 + (16 x 3)} (16 x 2) 2 (53 + 48) 32 2 (101) 32 202 32 Mass of oxygen liberated when 202 g of KNO 3 is heated = 32 g Percentage loss of mass = 15...
As per the equation, 2 {39 + 14 + (16 x 3)} (16 x 2) 2 (53 + 48) 32 2 (101) 32 202 32 Mass of oxygen liberated when 202 g of KNO 3 is heated = 32 g Percentage loss of mass = 15... Result
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