The total energy (T.E) of the electron in stationary orbit
The energy of electron revolving in a stationery orbit is of two types. Kinetic energy due to velocity and potential energy due to the position of the electron. Now (-ve is for charge of an electron) Now T.E = K.E + P.E Spectral series of hydrogenati..
The energy of electron revolving in a stationery orbit is of two types. Kinetic energy due to velocity and potential energy due to the position of the electron. Now (-ve is for charge of an electron) Now T.E = K.E + P.E Spectral series of hydrogenati..Suggested solution:
Number of half-lives, ..
Number of half-lives, ..Suggested solution:
We know that the activity of a radioactive sample is directly proportional to the number of atoms present. ..
We know that the activity of a radioactive sample is directly proportional to the number of atoms present. ..Definition -Average Life or Mean Life
The total lifetime of all the atoms of the element divided by the total number of atoms present initially in the sample of the element. ..
The total lifetime of all the atoms of the element divided by the total number of atoms present initially in the sample of the element. ..Suggested solution:
Since the valency of silver is 1, therefore each atom of silver contributes one free electron. 108 kg of silver contains 6.023 x 10 2 6 atoms. Number of electrons per unit volume of silver, Now, or..
Since the valency of silver is 1, therefore each atom of silver contributes one free electron. 108 kg of silver contains 6.023 x 10 2 6 atoms. Number of electrons per unit volume of silver, Now, or..
Suggested answer:
Let us first calculate the distance (OB = OC = OA = OD) of each charge from O. Potential at O due to charges at A, B, C and D is given by ..
Let us first calculate the distance (OB = OC = OA = OD) of each charge from O. Potential at O due to charges at A, B, C and D is given by ..Note:
For an infinitely long conductor, ..
For an infinitely long conductor, ..Suggested solution:
u = -25 cm, f = -10 cm v = ? On simplification, v = -16.67 cm Area enclosed by the image = (-2 cm) 2 = 4cm ..
u = -25 cm, f = -10 cm v = ? On simplification, v = -16.67 cm Area enclosed by the image = (-2 cm) 2 = 4cm ..
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