Suggested answer:
a) 2x 2 +x-3 Let p(x) = 2x 2 +x-3 The factors of the constant 3 are +1, -1, +3, -3. Let us find p(1) = 2+1-3 = 0 Divide 2x 2 +x-3 by x-1 to get the other factor. Hence 2x 2 +x-3 = (2x+3) (x-1) . b) 5x 2 +6x-8..
a) 2x 2 +x-3 Let p(x) = 2x 2 +x-3 The factors of the constant 3 are +1, -1, +3, -3. Let us find p(1) = 2+1-3 = 0 Divide 2x 2 +x-3 by x-1 to get the other factor. Hence 2x 2 +x-3 = (2x+3) (x-1) . b) 5x 2 +6x-8..Sets
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