Solution
2 M solution of H 2 O 2 means 2 mol of H 2 O 2 in one litre of the solution. Molar mass of H 2 O 2 = (2x1 + 2x16) g/mol =(2 + 32) g/mol = 34 g/mol Thus, there are 68 g (= 2 x 34 g) of H 2 O 2 in one litre of the solution. So, Mass of H 2 O 2 in 100 ..
2 M solution of H 2 O 2 means 2 mol of H 2 O 2 in one litre of the solution. Molar mass of H 2 O 2 = (2x1 + 2x16) g/mol =(2 + 32) g/mol = 34 g/mol Thus, there are 68 g (= 2 x 34 g) of H 2 O 2 in one litre of the solution. So, Mass of H 2 O 2 in 100 ..Calculations
Let, The mass of the acid dissolved be = W g Volume of alkali used for complete neutralization of acid solution = V 1 mL Normality of the alkali solution = N 1 Then, we can write, V 1 mL of alkali solution having normality N 1 = Wg a..
Let, The mass of the acid dissolved be = W g Volume of alkali used for complete neutralization of acid solution = V 1 mL Normality of the alkali solution = N 1 Then, we can write, V 1 mL of alkali solution having normality N 1 = Wg a..Solution:
The acceleration produced in any body due to the gravitational pull of the Earth does not depend on the mass of the body. So the acceleration produced in the 3 kg mass will also be 5 m/s 2 . 02. Calculate the height of a bridge if a stone dropped from it takes six seconds to to..
Solution
Mass of the substance taken = 0.2 g Volume of air displaced = 30 mL Temperature = 27 o C = (27 + 273) K = 300 K Atmospheric pressure = (756 - 26) mm Hg = 730 mm Hg Then, Therefore, Volume of the vapours at NTP = 22.5 mL Then, ..
Mass of the substance taken = 0.2 g Volume of air displaced = 30 mL Temperature = 27 o C = (27 + 273) K = 300 K Atmospheric pressure = (756 - 26) mm Hg = 730 mm Hg Then, Therefore, Volume of the vapours at NTP = 22.5 mL Then, ..Solution
(i) Since HCl is a strong acid, it completely ionizes and therefore, H 3 O + ions concentration is equal to that of the acid itself i.e., [H 3 O + ] = [HCl] = 0.001 M = 1 x 10 - 3 M now, pH = -log [H 3 O + ] pH = -log [1 x 10 - 3 ] = -(-3) log 10 = 3 (log 10 =1) (..
(i) Since HCl is a strong acid, it completely ionizes and therefore, H 3 O + ions concentration is equal to that of the acid itself i.e., [H 3 O + ] = [HCl] = 0.001 M = 1 x 10 - 3 M now, pH = -log [H 3 O + ] pH = -log [1 x 10 - 3 ] = -(-3) log 10 = 3 (log 10 =1) (..Solution
Heat capacity of solution = Mass of solution x Specific heat capacity Total mass of solution = 100 + 100 = 200 ml Heat capacity of solution = 200 x 4.2 = 840 JK - 1 Heat change in the reaction = Heat capacity x Rise in temperature = (840 JK - 1 ..
Heat capacity of solution = Mass of solution x Specific heat capacity Total mass of solution = 100 + 100 = 200 ml Heat capacity of solution = 200 x 4.2 = 840 JK - 1 Heat change in the reaction = Heat capacity x Rise in temperature = (840 JK - 1 ..Solution
D H c o m b of Glucose (C 6 H 1 2 O 6 ) = - 2880 kJ mol - 1 14. Calculate the enthalpy change of combustion of cyclopropane at 298 K. The enthalpy of formation of CO 2 ( g ) , H 2 O ( l ) and propane ( g ) are -393.5, -285.8 and ..
D H c o m b of Glucose (C 6 H 1 2 O 6 ) = - 2880 kJ mol - 1 14. Calculate the enthalpy change of combustion of cyclopropane at 298 K. The enthalpy of formation of CO 2 ( g ) , H 2 O ( l ) and propane ( g ) are -393.5, -285.8 and ..Solution
>. The excess acid required 154 mL of N/10 NaOH for neutralization. Calculate the percentage of nitrogen in the compoun..
Solution of Right Angled Triangles
Solution of Right Angled Triangles - To solve a right angled triangle, we need to find out the unknown sides and the angles with the help of t-ratios. To find a side, usually we take such t-ratios that involve the unknown sides. In the figure, AB = 100 cm, find (i) x and (ii) y...
Solution of Right Angled Triangles - To solve a right angled triangle, we need to find out the unknown sides and the angles with the help of t-ratios. To find a side, usually we take such t-ratios that involve the unknown sides. In the figure, AB = 100 cm, find (i) x and (ii) y...Calculation of molecular mass of the solute from elivation in boiling point
D T b = k b m (1) If W B gms of the solute is dissolved in W A gms of the solvent then (where M B is the molar mass of the solute) From (1) and (2)..
D T b = k b m (1) If W B gms of the solute is dissolved in W A gms of the solvent then (where M B is the molar mass of the solute) From (1) and (2)..See what our Users say :
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