Step I
The two half-cell reactions are written in such a way that the reaction taking place at the left hand electrode is written as an oxidation reaction and that taking place at the right electrode is written as reduction reactio..
Steps:
The first 2 electrons will go to the 1 st shell = K Shell (2n 2 ) The next shell L takes a maximum of 8 electrons (2n 2 ) In this way 2 + 8 = 10 electrons have been accommodated. The next 2 electrons go to the M Shell. K ..
Steps
Write the symbol of the ions of the compound. Cation (positive ion) is written on the left hand side and the anion (negative ion) is written on the right hand side. Put the valency number of the radical or ion below the symbol of the element. Alternatively cross the positive and negative..
Write the symbol of the ions of the compound. Cation (positive ion) is written on the left hand side and the anion (negative ion) is written on the right hand side. Put the valency number of the radical or ion below the symbol of the element. Alternatively cross the positive and negative..Step 2:
Find the co-ordinates of each vertex of the feasible region. These co-ordinates can be obtained from the graph or by solving the equation of the line..
Step I :
Express the differential equation in the form f(x) dx = g(y) d..
Steps
Calculate empirical formula. Use vapor density if given. If molecular weight given, calculate 'n' using this formula. Molecular formula = n x empirical formul..
Calculate empirical formula. Use vapor density if given. If molecular weight given, calculate 'n' using this formula. Molecular formula = n x empirical formul..Step 2:
Form the combination (x 1 , x 2 , x 3 ) for the rows identified in step 1. Put x i if x i = 1 x i if x i = 0 For the 1 s t row, the expression is x 1 .x 2 .x 3 2 n d row, the expression is x 1 .x 2 .x 3 ' 3 r d row, the expression is x 1..
Step 2
>(ii) The oxidation number of chromium on the left is +6 and on the right is +3. Each chromium atom must gain three electrons. Since there are two Cr atoms, add 6e - on the left. (iii) Since the reaction takes place in acidic medium add 14H + on the left to equate the net charge..
>(ii) The oxidation number of chromium on the left is +6 and on the right is +3. Each chromium atom must gain three electrons. Since there are two Cr atoms, add 6e - on the left. (iii) Since the reaction takes place in acidic medium add 14H + on the left to equate the net charge..Step 2:
4a 2 x 2 + 4abx = -4ac [Transposing 4ac to R..
Step 2:
f ' (x) = (x - 6) (x - 4) + (x - 4) (x - 8) + (x - 6) (x - 8) f '(x)= (x 2 -10x + 24) + (x 2 - 12x + 32)+ (x 2 - 14x + 48) = 3x 2 - 36x + 104 f '(x) is defined for all values on the interval (4,10). \ f '(x) is differentiabl..
Result
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