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Write the symbol of the ions of the compound. Cation (positive ion) is written on the left hand side and the anion (negative ion) is written on the right hand side. Put the valency number of the radical or ion below the symbol of the element. Alternatively cross the positive and neg..
Write the symbol of the ions of the compound. Cation (positive ion) is written on the left hand side and the anion (negative ion) is written on the right hand side. Put the valency number of the radical or ion below the symbol of the element. Alternatively cross the positive and neg..Step 2:
Solve f '(x) = 0 to get the critical values for f (x). Let these values be a, b, c. These are the points of maxima or minima. Arrange these values in ascending ord..
Step 2
>(ii) The oxidation number of chromium on the left is +6 and on the right is +3. Each chromium atom must gain three electrons. Since there are two Cr atoms, add 6e - on the left. (iii) Since the reaction takes place in acidic medium add 14H + on the left to equate the net charge..
>(ii) The oxidation number of chromium on the left is +6 and on the right is +3. Each chromium atom must gain three electrons. Since there are two Cr atoms, add 6e - on the left. (iii) Since the reaction takes place in acidic medium add 14H + on the left to equate the net charge..Linear equations in two variables
Linear equations in two variables - A Linear equation is a first degree algebraic expression with one,two or more variables equated to a constant. Graphically a linear equation with one or two variables..
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(2ax) 2 + 2(2ax)b +b 2 = b 2 - 4ac [Adding b 2 to both sides (square of the coefficient of x..
Step 1:
Since the two decision variable x and y are non-negative, consider only the first quadrant of xy- plane Draw the line ax + by = c ...(1) For each constraint, the line (1) divides the first quadrant in to two regions say R 1 and R 2 , suppose (x 1 , 0) is..
Since the two decision variable x and y are non-negative, consider only the first quadrant of xy- plane Draw the line ax + by = c ...(1) For each constraint, the line (1) divides the first quadrant in to two regions say R 1 and R 2 , suppose (x 1 , 0) is..Step 1:
Multiplying by 4 times the coefficient of x 2 on both sides i.e., 4..
Multiplying by 4 times the coefficient of x 2 on both sides i.e., 4..Step 3:
We have the following conditions on the variables x and y. a) Sum of the numbers is atleast 15 i.e., x + y 15 b) Difference of the numbers is at most 7 i.e., x - y 7 c) Since the x and y should be positive, we have two more conditions x > 0, y > 0 We call Z as objectiv..
We have the following conditions on the variables x and y. a) Sum of the numbers is atleast 15 i.e., x + y 15 b) Difference of the numbers is at most 7 i.e., x - y 7 c) Since the x and y should be positive, we have two more conditions x > 0, y > 0 We call Z as objectiv..Steps:
The first 2 electrons will go to the 1 s t shell = K Shell (2n 2 ) The next shell L takes a maximum of 8 electrons (2n 2 ). In this way 2 + 8 = 10 electrons have been accommodated. The next 2 electrons go to the M Shell..
First step
Sulphur dioxide reacts with water to liberate nascent hydrogen. 2H 2 O(l) + SO 2 (g) -----------------> H 2 SO 4 (aq) + 2[H]water sulphur dioxide sulphuric acid nascent hydrog..
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