how to solve equations with variables on both sides step by step


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Calcium Chloride balanced equation Write the symbol of the ions of the compound. Cation (positive ion) is written on the left hand side and the anion (negative ion) is written on the right hand side. Put the valency number of the radical or ion below the symbol of the element. Alternatively cross the positive and neg..
Steps
- Carboxylation - Glycolytic reversal - Regeneration of RUBP Photorespiration Light dependent up take of O 2 by cells and release of CO 2 without producing ATP and NADPH. During high conc. of O 2 and high temperature. RUBISCO act as RUBP oxygenase. RUBP splits into PGA and phosphoglycolate...
Steps
hydrogen sulphid formation Write the symbols of the elements which form the compound. Below the symbol of each element write down its valency. Cross over the valencies of the atoms. ..
First step
Sulphur dioxide reacts with water to liberate nascent hydrogen. 2H 2 O(l) + SO 2 (g) -----------------> H 2 SO 4 (aq) + 2[H]water sulphur dioxide sulphuric acid nascent hydrog..
Steps:
The first 2 electrons will go to the 1 st shell = K Shell (2n 2 ) The next shell L takes a maximum of 8 electrons (2n 2 ) In this way 2 + 8 = 10 electrons have been accommodated. The next 2 electrons go to the M Shell. K L M 2 8 2 ..
Step II:
Prove that the statement P(1) holds good by putting n = 1 on one side of the statement and then simplifying it to take the form of the expression on the other side..
Step 1:
Find a value of the variable x for which the value of x 2 + 3x - 4 is equal to 0. Let x =1, Then, f(1) = (1) 2 + 3(1) - 4 = 0..
Step 1
For a differentiable function f (x), find f '(x). Equate it to zero. Solve the equation f '(x) = 0 to get the Critical values of f (x..
Step 2:
Solve f '(x) = 0 to get the critical values for f (x). Let these values be a, b, c. These are the points of maxima or minima. Arrange these values in ascending ord..
Step 3
The oxidation number of zinc has increased from 0 to +2 while that of hydrogen has decreased from +1 to 0. However, the oxidation number of chlorine remains same on both sides of the equation. Therefore, zinc is reducing agent while HCl is oxidizing agent in reaction and the ch..
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