Substitution Method
The solution is x = -9 and y = -2. Solve 43x + 31y = 241 (i) 31x + 43y = 277 (ii) By adding (i) and (ii), we get 74x + 74y = 518 x + y = 7 (iii) By subtracting (ii) from (i) 12..
The solution is x = -9 and y = -2. Solve 43x + 31y = 241 (i) 31x + 43y = 277 (ii) By adding (i) and (ii), we get 74x + 74y = 518 x + y = 7 (iii) By subtracting (ii) from (i) 12..Substitution Method-Simultaneous EquationsThe solution is x = -9 and y = -2. Solve 43x + 31y = 241 (i) 31x + 43y = 277 (ii) By adding (i) and (ii), we get 74x + 74y = 518 x + y = 7 (iii) By subtracting (ii) from (i) 12..
The solution is x = -9 and y = -2. Solve 43x + 31y = 241 (i) 31x + 43y = 277 (ii) By adding (i) and (ii), we get 74x + 74y = 518 x + y = 7 (iii) By subtracting (ii) from (i) 12..Solve: |5 - 8x| - 3 = 18
Solve: |5 - 8 x | - 3 = 18 => 2, -3.25 or -2, 3.25 or -2, -3.25 or 2, 3.25..
Solve the system by substitution:2x + 6y = 85x = - 15y + 25
Solve the system by substitution: 2 x + 6 y = 8 5 x = - 15 y + 25 => (3, 3) or No solution or Infinite solution or (15, 0)..
Equations Solving and Graph Problems
Question 1 - Question: Solve the following equation: 3(x-1)=8 Answer: 3(x-1)=8 3x-3=8 3x=8+3 3x=..
Question 1 - Question: Solve the following equation: 3(x-1)=8 Answer: 3(x-1)=8 3x-3=8 3x=8+3 3x=..Question 8
Question: Solve the following equation: Answer: 2x-(1-2x) = 5-3(1+x) 2x-1+2x = 5-3-3x 4x+3x = 5-3+1 7..
Question: Solve the following equation: Answer: 2x-(1-2x) = 5-3(1+x) 2x-1+2x = 5-3-3x 4x+3x = 5-3+1 7..Question 8
Question: Given D ABC and DE||BC. [2 Mark] AD = 4x - 3 DB = 3x - 1 AE = 8x - 7 EC = 5x - 3 Find the value of x. Answer: Since DE||BC, using Basic Proportional..
Question: Given D ABC and DE||BC. [2 Mark] AD = 4x - 3 DB = 3x - 1 AE = 8x - 7 EC = 5x - 3 Find the value of x. Answer: Since DE||BC, using Basic Proportional..Solve for x.18x + 8 = x2
Solve for x . 1 8 x + 8 = x 2 => - 3 and 18 or - 2 and 18 or 2 and 18 or 3 and 18..
Suggested answer:
= (14 - 12) - (7 - 3) + (4 - 2) = 2 - 4 + 2 = 0 The system may have infinite number of solutions or no solution. Put x = k in (1) and (2) and solve y + z = 6 - k 2..
= (14 - 12) - (7 - 3) + (4 - 2) = 2 - 4 + 2 = 0 The system may have infinite number of solutions or no solution. Put x = k in (1) and (2) and solve y + z = 6 - k 2..Method of Elimination
Solve: 3x - 4y = 20 (i) 5x + 6y = 8 (ii) Multiply (i) by 3 and (ii) by 2: Adding the two, 19x = 76 Substituting x = 4 i..
Solve: 3x - 4y = 20 (i) 5x + 6y = 8 (ii) Multiply (i) by 3 and (ii) by 2: Adding the two, 19x = 76 Substituting x = 4 i..See what our Users say :
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