|
Unlimited Tutoring & Homework Help
|
Hydrolysis of Salts
Hydrolysis of Salts - Dissolution of different salts in water does not always result in neutral solutions. For example, aqueous solution of copper sulphate is acidic whereas aqueous solution of sodium acetate is basic and aqueous solu..
Hydrolysis of Salts - Dissolution of different salts in water does not always result in neutral solutions. For example, aqueous solution of copper sulphate is acidic whereas aqueous solution of sodium acetate is basic and aqueous solu..Buffer Solution
A solution which resists any change of pH when a small amount of a strong acid or a strong base is added to it, is called a buffer solution or simply as a buffer. Alternatively, a buffer solution may be defined as a solutio..
Buffers
Certain solutions, such as that of ammonium acetate, have a tendency to resist any change in its hydronium ion concentration or pH, whenever a small amount of a strong acid or a strong base is added to it. This property of a solution is known as buffer action..
Hydrolysis of Salts
Dissolution of different salts in water does not always result in neutral solutions. For example, aqueous solution of copper sulphate is acidic whereas aqueous solution of sodium acetate is basic and aqueous solution of sodium chloride forms n..
Basic buffer
A buffer solution containing relatively large amounts of a weak base and its salt with a strong acid, is termed as a basic buffer. Such buffers have pH on the alkaline side i.e., pH is higher than 7 at 298 K. The pH of..
Degree of hydrolysis
If the original concentration of the salt in the solution is 'c' mol/litre and 'h' is the degree of hydrolysis at that concentration, then Initial Concentration c c 0 0 Concentration at eqilibrium c(1-h) c(1-h) ch ch K h = h 2 o..
If the original concentration of the salt in the solution is 'c' mol/litre and 'h' is the degree of hydrolysis at that concentration, then Initial Concentration c c 0 0 Concentration at eqilibrium c(1-h) c(1-h) ch ch K h = h 2 o..Degree of hydrolysis
pH of the hydrolysed salt solution [H + ] = ch Now, pH = -log [H + ] Now, -log K w = pK w - log K b = pK..
Action of an acid buffer
An acid buffer contains relatively large amounts of a weak acid (HA) and its salt with a strong base (say NaA). The buffer solution thus contains large concentration of HA and A - (due to the dissociation of the salt), apart from H 3 O + and OH -..
An acid buffer contains relatively large amounts of a weak acid (HA) and its salt with a strong base (say NaA). The buffer solution thus contains large concentration of HA and A - (due to the dissociation of the salt), apart from H 3 O + and OH -..i) Hydrolysis
Esters hydrolyzed by boiling water slowly to carboxylic acids and phenols. The hydrolysis is accelerated in the presence of mineral acid on alkali. The alkaline hydrolysis is known as saponification. This is because esters with high molecular mass (C 1 2 - C 1 7 ) give s..
Hydrolysis constant
The hydrolysis constant may be written as: The hydrolysis constant 'K h ', of the salt is inversely proportional to the dissociation constant, 'K b ' of the weak b..
The hydrolysis constant may be written as: The hydrolysis constant 'K h ', of the salt is inversely proportional to the dissociation constant, 'K b ' of the weak b.. Result
Pages   :     1     2     3     4     5     6     7     8     9     10     11
See what our Users say :
This tutor was excellent. very clear on all of the problems. I would like to have more tutoring from Tutor Vista
Best tutor ever. I can actually understand what to do in fraction and decimal division situations
Very good, Tutor was clear and guided me through the whole algebra problems
This Tutor Vista is GREAT! loved this session, it helped me heaps.

