implicit differentiation with ln

When a relation is expressed in the form f(x,y) = 0, that is, an equation involving both x and y ,then either variable is said to be an implicit function of the other. To differentiate the function is nothing but finding dy / d..

Derivative of Implicit Functions - Till now, the functions that we have discussed, are explicitly functions of x. We have defined y in terms of x. Suppose we have an equation f(x,y) = 0, which cannot be put in the form of y=f(x) to differentiate in the usual way, we can still ..

Till now, the functions that we have discussed, are explicitly functions of x. We have defined y in terms of x. Suppose we have an equation f(x,y) = 0, which cannot be put in the form of y=f(x) to differentiate in the usual way, we can still differentiate the equation f(x,..

The slope field of a certain differential equation is shown. Which of the following is the solution to that differential equation? => y = - 1 x + C or y = x 2 + C or y = ( x 2 + C ) 1 2 or y = ( x 3 + C ) 1 3 or y = ln x + C..

If 4 cy = 2sin ( cy + 29), then find y ′ using implicit differentiation. => - 1 c or - c y or - y c or y c or c y..

Differentiate the equation 8 x 2 - 7 xy + 4 y 2 = 5 with respect to x using implicit differentiation. => d y d x = ( 7 y - 8 x ) ( 4 y - 7 x ) or d y d x = ( 7 y - 1 6 x ) ( 7 x + 8 y ) or d y d x = ( 1 6 x - 7 y ) ( 7 x - 8 y ) or d y d x = 1 6 x 7 x - 8 y..

Differentiate: y = (ln 4 x ) sin x . => II or IV or I or III or V..

If y = cos - 1 x on (- 1, 1), then find d y d x using implicit differentiation. => 1 1 - x 2 or - 1 x 2 - 1 or - 1 1 + x 2 or - 1 1 - x 2 or 0..

If y = e x , then find d y d x using implicit differentiation. => 2 x 2 e x or x 2 e x or e - x or e x or 0..