Increasing and Decreasing Functions
Increasing and Decreasing Functions - This section explains how derivative can be used to check whether a function is increasing, decreasing or neither increasing nor decreasing in its domain. Let f be a function defined on an in..
Increasing and Decreasing Functions - This section explains how derivative can be used to check whether a function is increasing, decreasing or neither increasing nor decreasing in its domain. Let f be a function defined on an in..Derivative of a Function
Derivative of a Function - So far we have discussed the derivative of a function f(x) at a point 'a' which is in the domain of f. Suppose we want to find the derivative of the same function at a different point 'b', then we have to compute..
Derivative of a Function of a Function
The differentiation of function of a function is known as 'chain rule'. The chain rule is probably the most widely used differentiation rule in mathematics. If y is a differentiable function of u and u is a differentiable function of x, then the h..
Derivative of a Function of a Function
So far, we know how to differentiate functions like sin x and x 3 - 5. But how do we differentiate a function of a function? That is how can we differentiate sin (x 3 - 5)?So far, we know how to differentiate functions like sin x and x 3 - 5. But how do we di..
So far, we know how to differentiate functions like sin x and x 3 - 5. But how do we differentiate a function of a function? That is how can we differentiate sin (x 3 - 5)?So far, we know how to differentiate functions like sin x and x 3 - 5. But how do we di..Application of Derivatives Summary
. If m 1 m 2 = -1 the curves are orthogonal. The condition for the function f(x) to be increasing at x = a if f ' (a) >0. The condition for f(x) to be decreasing at x = a if f ' (a) < 0. A function f(x) is said to be strictly increasing at x = a if f(x)..
. If m 1 m 2 = -1 the curves are orthogonal. The condition for the function f(x) to be increasing at x = a if f ' (a) >0. The condition for f(x) to be decreasing at x = a if f ' (a) < 0. A function f(x) is said to be strictly increasing at x = a if f(x)..Derivative of Some Important Functions
The Derivative of Some Important Functions are: 1. Derivative of a Constant, 2. Derivative of x n where n is any integer, 3. Derivative of a Constant of a Function, 4. Derivative of Exponential Function..
Derivative of Inverse Trignometric Functions
Derivative of Inverse Trignometric Functions - Before finding the differentiation of inverse trigonometric functions, recall how the inverse trigonometric functions are defined and what the domain and range of each inverse trigonometric function. Fo..
Derivative of Inverse Trignometric Functions - Before finding the differentiation of inverse trigonometric functions, recall how the inverse trigonometric functions are defined and what the domain and range of each inverse trigonometric function. Fo..Derivative of a Function (in general)
The derivative of the function f with respect to a variable x is the function f ' whose value at x is provided the limit exist..
The derivative of the function f with respect to a variable x is the function f ' whose value at x is provided the limit exist..Derivative of Inverse Trignometric Functions
The Derivative of Inverse Trignometric Functions includes: 1. sin - 1 x, 2. cos - 1 x, 3. tan - 1 x, 4. cot - 1 x, 5. sec - 1 x, 6. cosec - 1 ..
Derivative of Implicit Functions
Till now, the functions that we have discussed, are explicitly functions of x. We have defined y in terms of x. Suppose we have an equation f(x,y) = 0, which cannot be put in the form of y=f(x) to differentiate in the usual way, we can still differentiate the equation f(x,..
See what our Users say :
Tutor was excellent, asnwered the question rapidly and provided the information I needed to understand the problem.
Tutor helped me on every question and help me when i was confused. Thank you Tutor Vista
This Tutor Vista is GREAT! loved this session, it helped me heaps.
Tutor Vista tutors are pleasant and great to work with, they were very patient and explained everything that is simple to follow. I love working with them. - John Coakley
Looking for More Help!
