Question 5
Question: Solve the following equation: Answer: -58y-232 = -108y+18 -58y+108y = 18+232 50y=250 y=5..
Question: Solve the following equation: Answer: -58y-232 = -108y+18 -58y+108y = 18+232 50y=250 y=5..Note 5:
Composition of two continuous functions is continuou..
Example 5:
Plot the graph of x+3y=6. Use the graph to find a) area between the line and axes b) value of y when x=..
Step 5:
(2ax + b) 2 = b 2 - 4ac [a 2 + 2ab + b 2 = (a+b) 2..
(2ax + b) 2 = b 2 - 4ac [a 2 + 2ab + b 2 = (a+b) 2..Relation
A x B = {(1, 3), (1, 5), (2, 3), (2, 5), (3, 3), (3, 5)} (i) = {(3, 3)} is the only pair which satisfies the relation x = y. R 'is equal to' is a subset of A x B. (ii) S = {(x, y) : x, y A x B, y = x + 2} = {(1, 3), (3, 5)}. These two pairs satisfy the relati..
A x B = {(1, 3), (1, 5), (2, 3), (2, 5), (3, 3), (3, 5)} (i) = {(3, 3)} is the only pair which satisfies the relation x = y. R 'is equal to' is a subset of A x B. (ii) S = {(x, y) : x, y A x B, y = x + 2} = {(1, 3), (3, 5)}. These two pairs satisfy the relati..Example 4:
Plot the graph of 5x-2y=5. Use the graph to find the area between the line and the axe..
Question 4
Question: Solve the following equation: 5x-(3x-1)=x-4 Answer: 5x-(3x-1)=x-4 5x-3x+1=x-4 2x-x=-4-1 x=-5..
Range
The set of second elements in a relation is called Range. In example (6), Range is set B = {3, 5..
Example:
Find at least 3 sets of values for the variables satisfying the equation. 2x+y=5 Express y in terms of x. y=5-2x Select three values of x, find corresponding values of y. x=0, y=5-(2x0)=5 x=1, y=5-(2x1)=3 x=-1, y=5-(-2)=7 Draw the x a..
Find at least 3 sets of values for the variables satisfying the equation. 2x+y=5 Express y in terms of x. y=5-2x Select three values of x, find corresponding values of y. x=0, y=5-(2x0)=5 x=1, y=5-(2x1)=3 x=-1, y=5-(-2)=7 Draw the x a..Example 1:
If R = {(1,2), (1,5),(2,4),(3,5)} Domain of R - 1 = {2, 5, 4} = Range of R Range of R - 1 = {1, 2, 3} = Domain o..
If R = {(1,2), (1,5),(2,4),(3,5)} Domain of R - 1 = {2, 5, 4} = Range of R Range of R - 1 = {1, 2, 3} = Domain o..See what our Users say :
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