intermediate algebra problems graph

Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, y = 0. Similarly, if we take another eq..

Simultaneous Equations - Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, y = 0. Similar..

). Its usefulness is seen through emphasis on mathematising practical situations.Solving of problems depends on the ability to understand and apply mathematical analysis to different situations. In this chapter, we will study some fundamental definitions and application..

(5y) + (5y) 2 = x 2 - 10xy + 25y 2 Find algebraically the value of 205 2 . 205 2 = (200 + 5) 2 = (200) 2 + 2 (200) (5) + (5) 2 = 40000 + 2000 + 25 = 42025 If the expression 36x 2 + Kx + 25 is a perfect square, find K. Middle term of the given expressi..

will be = (x + 10) years After 10 years, Mr.R's age will be = (7x + 10) years By the given condition of the problem (7x + 10) = 3(x + 10) 7x + 10 = 3x + 30 7x - 3x = 30 - 10 4x = 20 or x = 5 Son's age is 5 years. Mr.R's age is 7 5 = 35 years Mr.R's age is 35 years and his son's age is 5 y..

Problems on Simultaneous Equations - If one number is thrice the other and their sum is 60, find the numbers. Let the numbers be x and y. x is 3 times y x = 3y (1) Sum of x and y is 60 x + y = 60 (2) Putting the value of x from (1) in (2), we get, 3y + y = 60 4y = 60 y = 15 Substituting y..

Question: Solve the following equation: Answer: 54y-45=14 y 54y-14y=45 40y=45 ..

Question: Solve the following equation: Answer: By cross-multiplication, we get (8x-3) (x-2) = (4x+1) (2x+5) 8x(x-2)-3(x-2) = 4x(2x+5)+1(2x+5) ..

Question: Solve the following equation: Answer: 42y-42 = 35y-21 42y-91y = -21+42 -49y = 21 ..

Question: Find the values of a so that x=1, y=2 is a solution of: (a) 2x+ay=10 (b) ax+2y=6 (c) x+2y=a Answer: (a) 2x+ay=10, substitute x=1, y=2 2(1)+a(12) = 10 2+2a=10 2a=8 a=4 (b) ax+2y=6, substitute x=1, y=2 a(1)+2(2)=6 a+4=6 a=6-4 a=2 x+2y=a , substitute x=1, y=2 1+2(2)=a 1+4=a a=5..