intervals function

We can take the value of f at a (i.e., f(a)) as first estimate for average value of the function. Divide [a, b] into two equal parts such that then the second estimate of the average value of the function can be taken as second estimate of the average value of the functionh..

Choose the interval on which the function y = ( x + 2) 2 is increasing. => [- 2, ∞) or [- ∞, ∞] or (- ∞, - 2] or (- ∞, ∞)..

Find the range of the function in interval notation. y = - x 2 + 2 => (- ∞, 2] or [- 2, ∞) or (- ∞, 2) or [2, ∞) or (- ∞, - 2]..

Choose the interval on which the function y = | x + 2| + | x - 1| - 2 is decreasing. => [- 2, 2] or [- 2, ∞) or (- ∞, ∞) or (-∞, - 2]..

In which interval does the function f ( x ) = 2 x 3 - 3 x 2 - 12 x + 10 increase? => R - {0, 1, 2} or (- 1, 2) or (- ∞, - 1) ∪ (2, ∞) or (- ∞, - 1] ∪ [2, ∞) or (0, ∞)..

In which interval does the function f ( x ) = x 2 - 3 x - 2 x + 3 increase? => (- 3, ∞) or (- ∞, - 7] ∪ [1, ∞) or ( 7 3 , ∞) or (- ∞, - 7) ∪ (1, ∞) or (- 7, 1)..

Find the interval for which the function f ( x ) = x 2 + 2 5 6 x 2 increases. => (0, 4 ) or (- ∞, ∞) or (- 4 , 0) U (4 , ∞) or (- 4 , 4 )..

Find the value in the interval, which satisfies the Mean Value Theorem for the function f ( x ) = 2 + x 3 on [- 1, 2]. => 0 or 1 1 3 or 2 or 1 or 3..

Find the value in the interval, which satisfies the Mean Value Theorem for the function f ( x ) = x - x 3 on [- 2, 1]. => 1 or - 1 or 0 or 6 or 1 3..

Find the value in the interval, which satisfies the Mean Value Theorem for the function f ( x ) = ( x - 1)( x - 2) on [0, 4]. => 3 or 1 or 5 2 or - 2 or 2..