Is 0 a solution of the equation 4 = 2t - 4?
Is 0 a solution of the equation 4 = 2 t - 4? => No or Yes..
Find the exact solution of the equation 2(40-x14) = 80.
Find the exact solution of the equation 2( 4 0 - x 1 4 ) = 80. => x = - 14 or x = 14 or x = 1 14 or x = - 1 14..
Solution
(i) 208.91 has five significant figures. (ii) 0.00456 has three significant figures. (iii) 453 has three significant figures. (iv) 2.945 x 10 4 has four significant figures. (v) 0.346 has three significant figures. 2. Express 0..
Solution:
Gram molecular mass of H 2 SO 4 = (2 x 1) + (1 x 32) + (4 x 16) = 98 g Mass of 1 mole of H 2 SO 4 = 98 g No. of grams of H 2 SO 4 present in 0.05 mole of it =? Mole : Mass 1 : 98 0.05 : x x = ..
Solution:
1 GMM of water (H 2 O) = 2 x 1 + 16 = 18g. 18g = 1 mole Xg = 0.4 moles 0.4 moles of water weighs 7.2..
1 GMM of water (H 2 O) = 2 x 1 + 16 = 18g. 18g = 1 mole Xg = 0.4 moles 0.4 moles of water weighs 7.2..Solution
In the resulting solution, [Ca + + ] = 0.0025M. [C 2 O 4 2 - ] = 1 x 10 - 7 M. [Ca + + ][C 2 O 4 2 - ] = 0.0025 x 10 - 7 = 2.5 x 10 - 1 0 This is less than the solubility pro..
Solution
Mass number of 1 4 C is 14. So 14 g of 1 4 C contain 6.023 x 10 2 3 atoms of 1 4 C = 3.012 x 10 2 0 atoms Number of neutrons in 1 atom of 1 4 C = 14 - 6 = 8 Number of neutrons in 7 mg of 1 4 C = (8 x 3...
Mass number of 1 4 C is 14. So 14 g of 1 4 C contain 6.023 x 10 2 3 atoms of 1 4 C = 3.012 x 10 2 0 atoms Number of neutrons in 1 atom of 1 4 C = 14 - 6 = 8 Number of neutrons in 7 mg of 1 4 C = (8 x 3...Solution:
Molecular formula = SO 2 Molecular weight = 1 x 32 + 2 x 16 = 64 g64g of SO 2 occupies 22.4 L32 g of SO 2 = ? Volume of 32 g of SO 2 is 11.2 litr..
Molecular formula = SO 2 Molecular weight = 1 x 32 + 2 x 16 = 64 g64g of SO 2 occupies 22.4 L32 g of SO 2 = ? Volume of 32 g of SO 2 is 11.2 litr..Solution:
Molecular weight of N 2 = 2 x 14 = 28 g28 g of N 2 at STP occupies = 22.4 L 2.8 g of N 2 at STP = ?28 g of N 2 = 22.4 L2.8g of N 2 = ? 2.8 g of N 2 at STP occupies a volume of ..
Molecular weight of N 2 = 2 x 14 = 28 g28 g of N 2 at STP occupies = 22.4 L 2.8 g of N 2 at STP = ?28 g of N 2 = 22.4 L2.8g of N 2 = ? 2.8 g of N 2 at STP occupies a volume of ..Solution:
Cl = 35.51 mole of a substance = 22.4 L1 Mole of a substance = 1 GMM1 GMM of Cl 2 = 71 g71 g of Cl 2 = 22.4 L7.1 g of Cl 2 = ? 7.1 g of Cl 2 will occupy a volume of 2.24 litr..
Cl = 35.51 mole of a substance = 22.4 L1 Mole of a substance = 1 GMM1 GMM of Cl 2 = 71 g71 g of Cl 2 = 22.4 L7.1 g of Cl 2 = ? 7.1 g of Cl 2 will occupy a volume of 2.24 litr..See what our Users say :
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