Is 2 a solution of the equation 12 ÷ c = 6?
Is 2 a solution of the equation 12 ÷ c = 6? => No or Yes..
Solution:
f '(x) = 6x 2 - 42x + 36 f '(x) = 0 x = 1 and x = 6 are the critical values f ''(x) =12x - 42 If x =1, f ''(1) =12 - 42 = - 30 < 0 x =1 is a point of local maxima of f (x). Maximum value = 2(1) 3 - 21(1) 2 + 36(1..
f '(x) = 6x 2 - 42x + 36 f '(x) = 0 x = 1 and x = 6 are the critical values f ''(x) =12x - 42 If x =1, f ''(1) =12 - 42 = - 30 < 0 x =1 is a point of local maxima of f (x). Maximum value = 2(1) 3 - 21(1) 2 + 36(1..Solution
C 6 0 molecule is a symmetrical structure of fused-ring of aromatic system containing 20 hexagons and 12 pentagons of sp 2 hybridized C atoms. The structure bends around and closes to form a soccer ball shaped molecule. It is therefore, called buckyball or C 6..
Solution:
f (x) = x 3 - 6x 2 + 9x + 15 f ' (x) = 3x 2 -12x + 9 = 3(x 2 - 4x + 3) = 3 (x - 1) (x - 3) Thus x = 1 and x = 3 are the only points which could be the points of local maxima or local minima. Let us examine for x=1 When x<1 (slightly less ..
f (x) = x 3 - 6x 2 + 9x + 15 f ' (x) = 3x 2 -12x + 9 = 3(x 2 - 4x + 3) = 3 (x - 1) (x - 3) Thus x = 1 and x = 3 are the only points which could be the points of local maxima or local minima. Let us examine for x=1 When x<1 (slightly less ..Solution
The reaction is: Molecular mass of iodopropane (CH 3 CH 2 CH 2 I)= 3 x 12 + 7 x 1 + 127 = 170 Molecular mass of propene (CH 2 -CH=CH 2 ) = 3 x 12 + 6 x 1= 42 170 g of 1-iodopropane will give propene = 42 g But the actual yie..
The reaction is: Molecular mass of iodopropane (CH 3 CH 2 CH 2 I)= 3 x 12 + 7 x 1 + 127 = 170 Molecular mass of propene (CH 2 -CH=CH 2 ) = 3 x 12 + 6 x 1= 42 170 g of 1-iodopropane will give propene = 42 g But the actual yie..Solutions
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The given problem is solved in the following table. Empirical formula = C 1 H 2 O 1 = CH 2 O Empirical formula mass = (12 x 1) + (1 x 2) + (16 x 1) = 30 Molecular mass = 180 (given) Ratio of the molecular mass to empirical formula mass Molecular for..
The given problem is solved in the following table. Empirical formula = C 1 H 2 O 1 = CH 2 O Empirical formula mass = (12 x 1) + (1 x 2) + (16 x 1) = 30 Molecular mass = 180 (given) Ratio of the molecular mass to empirical formula mass Molecular for..Solution
100 g of chlorophyll contains 2.68 g of Mg 1 mole of Mg = 24 g of Mg = 6.023 x 10 2 3 atom of Mg 24 g of Mg contains, 6.023 x 10 2 3 atom of Mg =1.34 x 10 2 1 Mg atoms 13. A sample of gaseous substance weighing 0.5 g occupies..
100 g of chlorophyll contains 2.68 g of Mg 1 mole of Mg = 24 g of Mg = 6.023 x 10 2 3 atom of Mg 24 g of Mg contains, 6.023 x 10 2 3 atom of Mg =1.34 x 10 2 1 Mg atoms 13. A sample of gaseous substance weighing 0.5 g occupies..Solution
Mass of the compound taken = 0.2 g Mass of CO 2 formed = 0.296 g Mass of H 2 O formed = 0.12 g Therefore, the percentage of O = 100 - (40.0 + 6.67) = 53.33(by differen..
Mass of the compound taken = 0.2 g Mass of CO 2 formed = 0.296 g Mass of H 2 O formed = 0.12 g Therefore, the percentage of O = 100 - (40.0 + 6.67) = 53.33(by differen..Solution
(1) 93 million miles = 93 x 10 6 miles 1 mile = 1.60934 km = 1.60934 x 10 3 m = 1.5 x 10 1 1 m (2) 5 feet and 2 inch = (5 x 12 + 2) inch = 62 inch 1 inch = 2.54 x 10 - 2 m then, 5 feet and 2 inch = 62 inch ..
(1) 93 million miles = 93 x 10 6 miles 1 mile = 1.60934 km = 1.60934 x 10 3 m = 1.5 x 10 1 1 m (2) 5 feet and 2 inch = (5 x 12 + 2) inch = 62 inch 1 inch = 2.54 x 10 - 2 m then, 5 feet and 2 inch = 62 inch .. Result
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