Is 2 a solution of the equation a2 + 3 = 8?
Is 2 a solution of the equation a 2 + 3 = 8? => Yes or No..
Approximate the solution of the linear equation 3x - 8.2 = 2(1.3x - 5...
Approximate the solution of the linear equation 3 x - 8.2 = 2(1.3 x - 5.6) by using a graphing calculator. => 1.5 or 6.8 or 48.5 or - 7.5..
Determine the maximum number of positive and negative real solutions o..
Determine the maximum number of positive and negative real solutions of the equation P ( x ) = x 4 + 8 x 3 + 17 x 2 - 2 x - 24 = 0 . => Positive: 2, Negative: 2, x = 1, - 2, 3, - 4 or Positive: ..
Purification of Colloidal Sols
The colloidal solutions prepared by various methods usually contain electrolytes and other soluble substances as impurities. These impurities if not removed can destabilize the sols. Impurities are removed by the following methods: 1) Dialysis 2) Ultra-filtration ..
Solution:
Na - 11; 2, 8, 1Number of the valence shell - 3Therefore, sodium is placed in period 3 of the periodic tab..
Solution
According to the equation, if 2 moles of SO 3 are formed, 2 moles of SO 2 and 1 mole of O 2 are used up. Hence 1.6 moles of SO3 are formed from 1.6 moles of SO 2 and 0.8 mole of O 2 . Therefor..
According to the equation, if 2 moles of SO 3 are formed, 2 moles of SO 2 and 1 mole of O 2 are used up. Hence 1.6 moles of SO3 are formed from 1.6 moles of SO 2 and 0.8 mole of O 2 . Therefor..Solution:
Electron configuration: K L M 2 8 7 Number of valence electrons = 7Valency = 8 - 7 = 1Valence shell ..
Solution:
In 100g of the compound, masses of elements are as follows: In 100 grams of compound, 71.8 g are antimony and 28.2% sulphur. Empirical formula is Sb 2 S 3..
In 100g of the compound, masses of elements are as follows: In 100 grams of compound, 71.8 g are antimony and 28.2% sulphur. Empirical formula is Sb 2 S 3..Solution
For the reaction, K p = 1.80 x 10 - 3 kPa, K c = ? We know that, K p = K c (RT) n where n = n g ( p r o d u c t s ) - n g ( r e a c t a n t s ) For the given reaction, n = 2 + 1 - 2 = 1 So, K p = K c (RT) 1 = K c x RT R = 8..
For the reaction, K p = 1.80 x 10 - 3 kPa, K c = ? We know that, K p = K c (RT) n where n = n g ( p r o d u c t s ) - n g ( r e a c t a n t s ) For the given reaction, n = 2 + 1 - 2 = 1 So, K p = K c (RT) 1 = K c x RT R = 8..Solution
(a) Here the outermost shell corresponds to, n = 4. So, this element lies in the 4 t h period. (b) The outer electronic configuration of this element is 3d 1 0 4s 1 the energy of the '3d' orbitals is higher than that of '4s'. Therefore the last electron goes to the 3h..
Result
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