Is 44 a solution to the equation 54 - y = 15?
Is 44 a solution to the equation 54 - y = 15? => No or Yes..
Solution:
In the first compound hydrogen = 5.93% Oxygen = (100 -5.93) = 94.07% In the second compound hydrogen = 11.2% Oxygen = (100 -11.2) = 88.88% Ratio of the masses of oxygen that combine with fixed mass of hydrogen 15.86: 7.9 or 2:1 The ratio illustrates the law of multiple proportio..
In the first compound hydrogen = 5.93% Oxygen = (100 -5.93) = 94.07% In the second compound hydrogen = 11.2% Oxygen = (100 -11.2) = 88.88% Ratio of the masses of oxygen that combine with fixed mass of hydrogen 15.86: 7.9 or 2:1 The ratio illustrates the law of multiple proportio..Solution
(1) 93 million miles = 93 x 10 6 miles 1 mile = 1.60934 km = 1.60934 x 10 3 m = 1.5 x 10 1 1 m (2) 5 feet and 2 inch = (5 x 12 + 2) inch = 62 inch 1 inch = 2.54 x 10 - 2 m then, 5 feet and 2 inch = 62 inch 1 mile = 1.60934 x 10 3 m, 1 min 60 x 60 s ..
(1) 93 million miles = 93 x 10 6 miles 1 mile = 1.60934 km = 1.60934 x 10 3 m = 1.5 x 10 1 1 m (2) 5 feet and 2 inch = (5 x 12 + 2) inch = 62 inch 1 inch = 2.54 x 10 - 2 m then, 5 feet and 2 inch = 62 inch 1 mile = 1.60934 x 10 3 m, 1 min 60 x 60 s ..Solution:
200 mL of CO 2 = 0.40 g 22.4 L of CO 2 = 12 + 32 (44g) Molecular weight = 2 x vapor density = 2 x 22.22 = 44.44..
200 mL of CO 2 = 0.40 g 22.4 L of CO 2 = 12 + 32 (44g) Molecular weight = 2 x vapor density = 2 x 22.22 = 44.44..Solution:
Mass of the reactants = 10gMass of the products = 4.4 + 5.6g = 10gSince the mass of the reactants is equal to the mass of the products, the observations are in agreement with the law of conservation of mas..
Solution:
Mass of 56 ml of carbon dioxide at STP = 0.11 g Mass of 22400 ml of carbon dioxide = ? Mass : Volume 0.11 g : 56 ml x g : 22400 ml Mass of 22400 ml of carbon dioxide at STP = 44 g Molar Mass of carbon dioxide = 44 g/mo..
Mass of 56 ml of carbon dioxide at STP = 0.11 g Mass of 22400 ml of carbon dioxide = ? Mass : Volume 0.11 g : 56 ml x g : 22400 ml Mass of 22400 ml of carbon dioxide at STP = 44 g Molar Mass of carbon dioxide = 44 g/mo..Solution:
Force (F) = 225 N Acceleration (a) = 2.5 m/s 2 Force (F) = ma Mass of the body = 90..
Force (F) = 225 N Acceleration (a) = 2.5 m/s 2 Force (F) = ma Mass of the body = 90..Solution
Decreasing order of 's' character C-3 > C-2 > C-1 15. Why is NF 3 pyramidal, while BF 3 , is triangular planar, though both are tetra atomic molecule..
Solution
The degree of hardness of water is defined as the number of parts by mass of calcium carbonate, equivalent to various calcium and magnesium present in one million parts of mass of water. It is expressed in ppm. Now, 10 6 g of water contains CaCO 3 = 44 mg By definition, 1 mol of CaCO 3..
The degree of hardness of water is defined as the number of parts by mass of calcium carbonate, equivalent to various calcium and magnesium present in one million parts of mass of water. It is expressed in ppm. Now, 10 6 g of water contains CaCO 3 = 44 mg By definition, 1 mol of CaCO 3..Solution
For isothermal reversible expansion of ideal gas..
For isothermal reversible expansion of ideal gas..See what our Users say :
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