Is 5 a solution of the equation 7x + 4 - 4x = 19?
Is 5 a solution of the equation 7 x + 4 - 4 x = 19? => No or Yes..
Equivalent Conductance (^eq.)
It is defined as the conductance of that volume of solution which has one equivalent dissolved in it. V = Volume of solution which has one equivalent in it. N normality (Number of equivalents per liter or 1000c..
It is defined as the conductance of that volume of solution which has one equivalent dissolved in it. V = Volume of solution which has one equivalent in it. N normality (Number of equivalents per liter or 1000c..Solution
Naphthalene is..
Naphthalene is..Solution
The possible isomers of the aromatic compound having molecular formula C 7 H 7 Cl are benzyl chloride and ortho chlorotoluene and para chlorotoluene...
The possible isomers of the aromatic compound having molecular formula C 7 H 7 Cl are benzyl chloride and ortho chlorotoluene and para chlorotoluene...Solution:
Cl = 35.5 1 mole of a substance = 22.4L 1 Mole of a substance = 1 GMM 1 GMM of Cl 2 = 71 g 71 g of Cl 2 = 22.4 L 7.1 g of Cl 2 = ? 7.1 g of Cl 2 will occupy a volume of 2.24 lite..
Cl = 35.5 1 mole of a substance = 22.4L 1 Mole of a substance = 1 GMM 1 GMM of Cl 2 = 71 g 71 g of Cl 2 = 22.4 L 7.1 g of Cl 2 = ? 7.1 g of Cl 2 will occupy a volume of 2.24 lite..Solution
The preparation of ozone needs a source of pure, cold and dry oxygen. The formation of ozone from oxygen is a reversible endothermic reaction..
The preparation of ozone needs a source of pure, cold and dry oxygen. The formation of ozone from oxygen is a reversible endothermic reaction..Solution:
In the first compound hydrogen = 5.93% Oxygen = (100 -5.93) = 94.07% In the second compound hydrogen = 11.2% Oxygen = (100 -11.2) = 88.88% Ratio of the masses of oxygen that combine with fixed mass of hydrogen 15.86: 7.9 or 2:1 The ratio illustrates the law of mul..
In the first compound hydrogen = 5.93% Oxygen = (100 -5.93) = 94.07% In the second compound hydrogen = 11.2% Oxygen = (100 -11.2) = 88.88% Ratio of the masses of oxygen that combine with fixed mass of hydrogen 15.86: 7.9 or 2:1 The ratio illustrates the law of mul..Solution
The electronic configurations of aluminium (At. no. 13) and fluorine (At. no. 9) atoms are 2,8,3 and 2,7 respectively. Aluminium has 3 electrons in excess of its nearest noble gas (neon) configuration. Fluorine is one electron short of its nearest noble gas (neon) configuration. Therefor..
The electronic configurations of aluminium (At. no. 13) and fluorine (At. no. 9) atoms are 2,8,3 and 2,7 respectively. Aluminium has 3 electrons in excess of its nearest noble gas (neon) configuration. Fluorine is one electron short of its nearest noble gas (neon) configuration. Therefor..Solution
In the resulting solution, [Ca + + ] = 0.0025M. [C 2 O 4 2 - ] = 1 x 10 - 7 M. [Ca + + ][C 2 O 4 2 - ] = 0.0025 x 10 - 7 = 2.5 x 10 - 1 0 This is less than the solubility product of calcium oxalate. Thus, precipitation of calcium oxalate does n..
Solution
The step, which involves the formation of Ca 3 + from Ca 2 + would have highest ionization energy...
The step, which involves the formation of Ca 3 + from Ca 2 + would have highest ionization energy...See what our Users say :
Very fast and clear. Made sure I understood the concepts instead of giving the answers to the problem.
This tutor was excellent. very clear on all of the problems. I would like to have more tutoring from Tutor Vista
Best tutor ever. I can actually understand what to do in fraction and decimal division situations
This Tutor Vista is GREAT! loved this session, it helped me heaps.
Looking for More Help!
