Is 7 a solution to the equation 70 + y = 77?
Is 7 a solution to the equation 70 + y = 77? => Yes or No..
Solution
Let the initial amounts of PCl 3 and Cl 2 placed in a container of volume V, be a and b moles respectively. According to the balanced chemical equation, x moles of PCl 3 combine with x moles of Cl 2 to form x moles of PCl 5 PCl 3 ( g ) + Cl 2 ( g ) g PCl 5 ( g ) 1 mol 1..
Let the initial amounts of PCl 3 and Cl 2 placed in a container of volume V, be a and b moles respectively. According to the balanced chemical equation, x moles of PCl 3 combine with x moles of Cl 2 to form x moles of PCl 5 PCl 3 ( g ) + Cl 2 ( g ) g PCl 5 ( g ) 1 mol 1..Choose the word for 77.
Choose the word for 77. => Seventy or Seventy-seven or Seven and seven or Seven..
Solution
The electronic configuration of atom 'D' has seven electrons in the outermost shell. Each 'D' atom should share a pair of electrons with another 'D' atoms to form a substance containing only 'D' .i.e., Hence, the formula of the substance is D 2 . It is a covalent compoun..
The electronic configuration of atom 'D' has seven electrons in the outermost shell. Each 'D' atom should share a pair of electrons with another 'D' atoms to form a substance containing only 'D' .i.e., Hence, the formula of the substance is D 2 . It is a covalent compoun..Solution
Phosphorus atom has five electrons in its outermost shell. It needs three more electrons to complete its shell. One electron is required to complete a chlorine atom, as its outer shell has seven electrons. Thus, one phosphorus atom can share one electron pair with each of the three chlor..
Phosphorus atom has five electrons in its outermost shell. It needs three more electrons to complete its shell. One electron is required to complete a chlorine atom, as its outer shell has seven electrons. Thus, one phosphorus atom can share one electron pair with each of the three chlor..Solution:
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..Solution:
Electron configuration: K L M 2 8 7 Number of valence electrons = 7Valency = 8 - 7 = 1Valence shell ..
Solution
The volume of H 2 SO 4 neutralised by N/10 NaOH can be obtained as follows: N a c i d x V a c i d = N a l k a l i x V a l k a l i Therefore, Volume of N/5 H 2 SO 4 used for neutralizing NH 3 = (100 - 77) mL = 23 mL Then, Percentage of nitrogen in the sample = ..
The volume of H 2 SO 4 neutralised by N/10 NaOH can be obtained as follows: N a c i d x V a c i d = N a l k a l i x V a l k a l i Therefore, Volume of N/5 H 2 SO 4 used for neutralizing NH 3 = (100 - 77) mL = 23 mL Then, Percentage of nitrogen in the sample = ..Solution :
(a) Valence electrons = 3; core electrons = 10(b) Valence electrons = 2; core electrons = 10(c) Valence electrons = 7; core electrons = 10(d) Valence electrons = 2; core electrons =..
Solution
The possible isomers of the aromatic compound having molecular formula C 7 H 7 Cl are benzyl chloride and ortho chlorotoluene and para chlorotoluene...
The possible isomers of the aromatic compound having molecular formula C 7 H 7 Cl are benzyl chloride and ortho chlorotoluene and para chlorotoluene...See what our Users say :
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