Suggested answer:
n t h term of (1,2,3,....) is n Subtracting (ii) from (i), we get ..
n t h term of (1,2,3,....) is n Subtracting (ii) from (i), we get ..Suggested answer:
i) 1.2 + 2.4 + 3.8 +.... to n terms The n t h term of (1,2,3,....n) is n. The n t h term of (2,4,8,...) is The n t h term of the given series is n2 n Subtracting (ii) from (i), we have ..
i) 1.2 + 2.4 + 3.8 +.... to n terms The n t h term of (1,2,3,....n) is n. The n t h term of (2,4,8,...) is The n t h term of the given series is n2 n Subtracting (ii) from (i), we have ..Question 4
Question: When n = 5 and r = 2, find the values of Answer: i) ii) ..
Question: When n = 5 and r = 2, find the values of Answer: i) ii) ..Question 1
Question: Answer: As n represents all positive integers, we have Multiplying the above terms of both sides respectively, we get Multiplying both sides of inequality by n!, we get ..
Question: Answer: As n represents all positive integers, we have Multiplying the above terms of both sides respectively, we get Multiplying both sides of inequality by n!, we get ..Suggested answer:
The determinant of coefficients ..
The determinant of coefficients ..Proof:
..
..To find the sum of a number of terms in Arithmetical Progression:
Let a=first term, d = common difference, l=t n =last term, s = required sum. Then, Writing the series in the reverse order, Adding together the two series, ..
Let a=first term, d = common difference, l=t n =last term, s = required sum. Then, Writing the series in the reverse order, Adding together the two series, ..To find the sum of n terms of a GP
Let a = First term, r = common ratio, n = number of terms. Multiply both sides of (i) by r, the common ratio. Subtracting (ii) from (i), we get ..
Let a = First term, r = common ratio, n = number of terms. Multiply both sides of (i) by r, the common ratio. Subtracting (ii) from (i), we get ..Suggested answer:
Subtracting (ii) from (i), we get ..
Subtracting (ii) from (i), we get ..Question 3
Question: Answer: i) ii) iii) ..
Question: Answer: i) ii) iii) ..See what our Users say :
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