More Formulae
1. a 2 + b 2 = (a + b) 2 - 2ab 2. a 2 + b 2 = (a - b) 2 + 2ab 5. (a + b) 2 = (a - b) 2 + 4ab 7. (a + b + c) 2 = a 2 + b 2 + c 2 + 2 (ab + bc + ca) 8. (a + b) 3 = a 3 + 3a 2 b + 3ab 2 + b 3 = a 3 + b 3 + 3ab (a + b) 9. (a - b) 3 = a 3 - 3a 2 b + 3ab 2 - b 3 = a 3 - b 3 ..
1. a 2 + b 2 = (a + b) 2 - 2ab 2. a 2 + b 2 = (a - b) 2 + 2ab 5. (a + b) 2 = (a - b) 2 + 4ab 7. (a + b + c) 2 = a 2 + b 2 + c 2 + 2 (ab + bc + ca) 8. (a + b) 3 = a 3 + 3a 2 b + 3ab 2 + b 3 = a 3 + b 3 + 3ab (a + b) 9. (a - b) 3 = a 3 - 3a 2 b + 3ab 2 - b 3 = a 3 - b 3 ..Summary
If all the terms of the polynomial have a common factor, we take out the common factor and factorise . If all the terms of the polynomial have a common factor, we take out the common factor and factorise . If the polynomial can be expressed as the difference of two squares, we use a 2 - b 2..
If all the terms of the polynomial have a common factor, we take out the common factor and factorise . If all the terms of the polynomial have a common factor, we take out the common factor and factorise . If the polynomial can be expressed as the difference of two squares, we use a 2 - b 2..Factorization
If a polynomial can be written as the product of two or more expressions, then each expression is called the factor of the given polynomial..
Summary
If all the terms of the polynomial have a common factor, we take out the common factor and factorise. If the polynomial can be expressed as the difference of two squares, we use a 2 - b 2 = (a + b) (a - b)..
Methods of Factorisation
(i) Common factors (ii) By expressing as difference of squares (iii) By grouping (iv) Trinomials (v) Sum or difference of cub..
Type (i) By taking out common factors from all the terms of a polynomial
8a 3 b - 6a 2 b 2 = 2a 2 b (4a - ..
8a 3 b - 6a 2 b 2 = 2a 2 b (4a - ..Trinomials
Expressions of the form ax 2 + bx + c are called trinomialsExpressions of the form ax 2 + bx + c are called trinomi..
Second Method:
x 2 + 8x + 15 = x 2 + 5x + 3x + 15 (after noticing that 5 + 3 = 8 and 5 3 = 15) = x(x +5) + 3(x + 5) = (x + 5) (x + 3) Resolve into factors: x 2 - 15x + 56 x 2 - 15x + 56 Take factors of 56 having their sum = -15 They are -8, -7. \ x 2 - 15x + 56 = x 2 - 7x - 8x + 56 \ x 2 - 15x +..
x 2 + 8x + 15 = x 2 + 5x + 3x + 15 (after noticing that 5 + 3 = 8 and 5 3 = 15) = x(x +5) + 3(x + 5) = (x + 5) (x + 3) Resolve into factors: x 2 - 15x + 56 x 2 - 15x + 56 Take factors of 56 having their sum = -15 They are -8, -7. \ x 2 - 15x + 56 = x 2 - 7x - 8x + 56 \ x 2 - 15x +..Second Method:
x 2 - 2x - 48 = x 2 - 8x + 6x - 48 = x(x - 8) + 6(x - 8) = (x - 8) (x + 6) When the coefficient of the highest power is not unity. i.e., type ax 2 bx c, when and b and c are integers. Multiply (3x + 2) (x + 4) and consider the result so obtained. = 3x (x + 4) +2 (x + 4) = 3x 2 + 12x..
x 2 - 2x - 48 = x 2 - 8x + 6x - 48 = x(x - 8) + 6(x - 8) = (x - 8) (x + 6) When the coefficient of the highest power is not unity. i.e., type ax 2 bx c, when and b and c are integers. Multiply (3x + 2) (x + 4) and consider the result so obtained. = 3x (x + 4) +2 (x + 4) = 3x 2 + 12x..Formula
A formula is formed by using:A formula is formed by using: (a) mathematical symbols and variables (b) given conditions, and (c) simplification. Some well known formulae are listed below: Area of a rectangle A = l x b A = Area l = Length b = Breadth Perimeter of a rectangle P = 2(l + b) P = Perimete..
A formula is formed by using:A formula is formed by using: (a) mathematical symbols and variables (b) given conditions, and (c) simplification. Some well known formulae are listed below: Area of a rectangle A = l x b A = Area l = Length b = Breadth Perimeter of a rectangle P = 2(l + b) P = Perimete.. Result
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