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Standard Deviation
Standard Deviation of a statistical data is defined as the positive square root of the arithmetic mean of the squared deviations of items from their arithmetic mean of the series under consideration. The standard deviati..
Standard Deviation
of a statistical data is defined as the positive square root of the arithmetic mean of the squared deviations of items from their arithmetic mean of the series under consideration. The standard deviation is denoted by s (sigma). The standar..
Standard Deviation for continuous series
In this series too deviations may be taken either from the actual mean or from standard mean. The calculations will be simplified if the deviation are taken from assumed mean..
Standard Deviation for continuous series
In this series too deviations may be taken either from the actual mean or from standard mean. The calculations will be simplified if the deviation are taken from assumed mean..
Give the control limits for 2 standard deviations around the mean, if ..
Give the control limits for 2 standard deviations around the mean, if the mean is 50 and standard deviation is 2. => 46, 92 or 44, 56 or 46, 54 or 48, 52..
Mean Deviation
The mean deviation of a statistical data is defined as the arithmetic mean of the numerical values of the deviations of items from some average value. Mean deviation is also known as average deviation . The mean de..
Calculation of Standard Deviation for discrete series
In the discrete series, when deviations are taken from actual mean, the formula is: ..
Find the mean, variance and standard deviation for the number of heads..
Find the mean, variance and standard deviation for the number of heads, when 20 coins are tossed. => 10, 5, 5 or 5, 5 2 , 5 2 or 10, 5 , 5 or 5, 5 2 , 5 2..
A survey asks 'How much time do you spend in front of the TV in one we..
A survey asks 'How much time do you spend in front of the TV in one week? Suppose the responses are normally distributed, the mean is 10 hours and the standard deviation is 2 hours. What value in hours is one standard deviation above the mean..
For a group of 200 candidates, the mean and standard deviation of scor..
For a group of 200 candidates, the mean and standard deviation of scores were found to be 40 and 15. Later on, it was discovered that the scores 43 and 35 were misread as 34 and 53. Find the corrected mean and standard deviation. => 39.955..
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