Methods of solving quadratic equations
There are four methods of solving quadratic equations. i) By factorization ii) By completing the squares iii) By using the formula iv) By graphi..
Methods to Solve Simultaneous Equations
Simultaneous Equations - Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, y = 0. Similar..
Simultaneous Equations - Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, y = 0. Similar..Second Method:
Divide AB = 8.4 cm internally in the ratio of 3 : 2. 1. Draw AB = 8.4 cm and through A draw another line AX at an acute angle to AB. 2. Make ABY = BAX so that BY is on the opposite side of AB to that of AX. 3. With suitable radius, cut off equal lengths AH, HJ, JK, KL and LM on AX. Similar..
Divide AB = 8.4 cm internally in the ratio of 3 : 2. 1. Draw AB = 8.4 cm and through A draw another line AX at an acute angle to AB. 2. Make ABY = BAX so that BY is on the opposite side of AB to that of AX. 3. With suitable radius, cut off equal lengths AH, HJ, JK, KL and LM on AX. Similar..Method II
a cos q + b sin q = c -----(i) (i) can be written as or a (1- t 2 ) + 2bt - c (1+t 2 ) = 0 This is a quadratic in 't' and can be solved...
a cos q + b sin q = c -----(i) (i) can be written as or a (1- t 2 ) + 2bt - c (1+t 2 ) = 0 This is a quadratic in 't' and can be solved...Substitution Method
Solve 2x - 9y = 0 (i) x - 18y = 27 (ii) From (i) 2x - 9y = 0 2x = 9y (iii) Substituting this value of x in (ii), we get, 9y - 36y = 54 - 27y = 54 y = -2 Substitute this value of y in (iii): = - ..
Solve 2x - 9y = 0 (i) x - 18y = 27 (ii) From (i) 2x - 9y = 0 2x = 9y (iii) Substituting this value of x in (ii), we get, 9y - 36y = 54 - 27y = 54 y = -2 Substitute this value of y in (iii): = - ..Method of Elimination (by Addition)
Solve the Systems of linear equations by Method of Elimination (by Addition): 3x - 4y = 20 (i) 5x + 6y = 8 (ii..
Simultaneous Equations-Method of Elimination
Method of Elimination - Solve: 3x - 4y = 20 (i) 5x + 6y = 8 (ii) Multiply (i) by 3 and (ii) by 2: Adding the two, 19x = 76 Substituting x = 4 in (ii), we get 5(4) + 6y = 8 6y = 8 - 20 6y = -12 y = ..
Method of Elimination - Solve: 3x - 4y = 20 (i) 5x + 6y = 8 (ii) Multiply (i) by 3 and (ii) by 2: Adding the two, 19x = 76 Substituting x = 4 in (ii), we get 5(4) + 6y = 8 6y = 8 - 20 6y = -12 y = ..Teacher asked Jeff to tell the method for solving 11815 ÷ 5 = 2..
Teacher asked Jeff to tell the method for solving 11815 ÷ 5 = 2363. He gave the answer as 2363 × 5. Was he correct? => Yes or No..
Graphical Method of Solution of a Linear Programming Problem
So far we have learnt how to construct a mathematical model for a linear programming problem. If we can find the values of the decision variables x 1 , x 2 , x 3 , ..... x n , which can optimise (maximize or minimize) the objective function Z, then we say that these values of x i are the optimal so..
3rd Method:
We can also solve the problem by substituting and get the same result. If a : b = c : d, then prove that Let or a = bk. Similarly, c = dk LH..
We can also solve the problem by substituting and get the same result. If a : b = c : d, then prove that Let or a = bk. Similarly, c = dk LH..See what our Users say :
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