Mirror Formula
Mirror Formula - In a spherical mirror, the distance of the object from its pole is called the object distance (u). the distance of the image from the pole of the mirror is called the image distance (v). You already know that the distance of the principal focus from th..
Mirror
In this poem, the mirror is the speaker. It is an autobiographical poem. The mirror talks about itself, its surroundings and the woman who uses it. In this way, it gives its observations in an objective way without any personal bia..
Numerical - 1
A 4.5 cm needle is placed 12 cm away from a convex mirror of focal length 15cm. Give the location of the image and the magnification. Describe what happens as the needle is moved farther from the mirror..
Optics Problems - Numerical 01
01. - A 4.5 cm needle is placed 12 cm away from a convex mirror of focal length 15cm. Give the location of the image and the magnification. Describe what happens as the needle is moved farther from the mirror..
Numericals
Chromium has mono atomic body-centred cubic structure. Its cell edge is 300 pm, what is its density? (Molar mass of Cr = 52 g mol - 1 , Avogadro number N = 6.023 x 10 2 3 mol..
Numericals
01. A body of mass 2kg is raised to a height of 25m. Calculate the potential energy possessed by the body. Solution: Mass of the body (m) = 2kg Height (h) = 25 m Potential energy of the body = mgh 02. A bag of rice weighs 75kg. To what height is it raised if the work done in lifting it is 4900 J. S..
01. A body of mass 2kg is raised to a height of 25m. Calculate the potential energy possessed by the body. Solution: Mass of the body (m) = 2kg Height (h) = 25 m Potential energy of the body = mgh 02. A bag of rice weighs 75kg. To what height is it raised if the work done in lifting it is 4900 J. S..Numericals
01. An object of mass 5 kg is lifted up through a distance of 2 meter. What is the work done? Solution: W = F x s Also, force acting on the object is F = mg [Newton's second law of motion] Mass of the object (m) = 5 kg Distance moved = 2m Therefore, Work done = F x s 02. How much work ..
01. An object of mass 5 kg is lifted up through a distance of 2 meter. What is the work done? Solution: W = F x s Also, force acting on the object is F = mg [Newton's second law of motion] Mass of the object (m) = 5 kg Distance moved = 2m Therefore, Work done = F x s 02. How much work ..Numericals
01. The Earth's gravitational force causes an acceleration of 5 m/s 2 in a 1 kg mass somewhere in space. How much will the acceleration of a 3 kg mass be at the same pla..
Numericals
01. A body of mass 2 kg is raised to a height of 25 m. Calculate the potential energy possessed by the bo..
Numericals
01. An object of mass 5 kg is lifted up through a distance of 2 metre. What is the work don..
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