Molar Volume
The molar volume [22.4L at STP] plays a vital role in stoichiometric calculations because it is the link between volume and mass in reactions involving gase..
Molar Volume
One mole of any gas at STP will have a volume of 22.4 L. This is called molar volume. The molar volume [22.4 L at STP] plays a vital role in stoichiometric calculations because it is the link between volume and mass in reactions involving gas..
One mole of any gas at STP will have a volume of 22.4 L. This is called molar volume. The molar volume [22.4 L at STP] plays a vital role in stoichiometric calculations because it is the link between volume and mass in reactions involving gas..Calculation of Degree of Dissociation
Calculation of Degree of Dissociation - Degree of Dissociation [ a ] - It is defined as the fraction of the total number of molecules undergoing dissociation at a given concentration. Example: If 100 molecules of acetic acid are added to H 2 O of which 10 molecules ionise, then or 1) If 0..
Calculation of Degree of Dissociation - Degree of Dissociation [ a ] - It is defined as the fraction of the total number of molecules undergoing dissociation at a given concentration. Example: If 100 molecules of acetic acid are added to H 2 O of which 10 molecules ionise, then or 1) If 0..Calculation of Degree of Dissociation - Degree of Dissociation [a]
It is defined as the fraction of the total number of molecules undergoing dissociation at a given concentration. Example: If 100 molecules of acetic acid are added to H 2 O of which 10 molecules ionise, then or 1) If 0.1M acetic acid has 25% degree of dissociation, what is the concentration of H 2 ..
It is defined as the fraction of the total number of molecules undergoing dissociation at a given concentration. Example: If 100 molecules of acetic acid are added to H 2 O of which 10 molecules ionise, then or 1) If 0.1M acetic acid has 25% degree of dissociation, what is the concentration of H 2 ..Applications of Kohlrausch's Law
Calculation of molar conductivity at infinite dilution (A o ) for weak electrolytes. Example: CH 3 CO..
Applications of Kohlrausch's Law
Applications of Kohlrausch's Law - Calculation of molar conductivity at infinite dilution (A o ) for weak electrolytes. Example: CH 3 COOH The value of for KCl, CH 3 COOK and HCl can be obtained by extrapolation (they are strong electrolytes..
Applications of Kohlrausch's Law - Calculation of molar conductivity at infinite dilution (A o ) for weak electrolytes. Example: CH 3 COOH The value of for KCl, CH 3 COOK and HCl can be obtained by extrapolation (they are strong electrolytes..Example: 3
About 40 g of sulphur is taken in an enclosed vessel containing 22.4 litres of oxygen. The sulphur is ignited. Calculate the volume of sulphur dioxide formed, and the mass of uncombined sulphur. (1 mole of S= 32 g: molar volume = 22.4 litr..
Normality Equation
Normality Equation - To calculate the volume of a definite solution required to prepare solutions of other normality, the following equation is used: N 1 V 1 =N 2 V 2 , where N 1 =initial normality and N 2 =normality of the new solution, a nd V 1 = initial volume and V 2 = volume of the n..
The conductance is expressed as
Specific conductance Equivalent or molar conductance The difference between the two has been clearly explained. Measurement of conductance is done using Wheatstone bridge method. The difference for electrolytes are: A.C. Source is used to prevent electrolysis Earphones are used..
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