Solution of Right Angled Triangles
To solve a right angled triangle, we need to find out the unknown sides and the angles with the help of t-ratios. To find a side, usually we take such t-ratios that involve the unknown sides. We have taken A because, the side opposite to A is the unknown side..
Solution of Right Angled Triangles
Solution of Right Angled Triangles - To solve a right angled triangle, we need to find out the unknown sides and the angles with the help of t-ratios. To find a side, usually we take such t-ratios that involve the unknown sides. In the figure, AB = 100 cm, find (i) x and (ii) y...
Solution of Right Angled Triangles - To solve a right angled triangle, we need to find out the unknown sides and the angles with the help of t-ratios. To find a side, usually we take such t-ratios that involve the unknown sides. In the figure, AB = 100 cm, find (i) x and (ii) y...Trigonometry
Trigonometry..
Trigonometry..Trigonometry
With trigonometry we can find the height of a building or the width of a river without actually climbing or crossing. Certain basic definitions are necessary to further develop this subject. The ratios of two sides of a triangle are taken. There are six possible combinations. Each ratio i..
With trigonometry we can find the height of a building or the width of a river without actually climbing or crossing. Certain basic definitions are necessary to further develop this subject. The ratios of two sides of a triangle are taken. There are six possible combinations. Each ratio i..Trigonometry
..
..Trigonometry Introduction
Introduction - In Greek 'Trigonon' means a triangle. 'Metron' means a measure. The combination of these two words gives us the word 'Trigonometry'. Trigonometry is the branch of mathematics that deals with the relations between the sides and angles of triangles. In our study we ..
Trigonometry (Continued)
Trigonometry (Continued)..
Trigonometry (Continued)..Trigonometry XI
Trigonometry XI..
Trigonometry XI..Trigonometry (Continued)
Summary - 1. In the principle value branches, the following formulae holds: sin -1 (sin x) = x, cos -1 (cos x) = x, tan -1 (tan x) = x, cos -1 (cot x) = x, sec -1 (secx) = x, cosec -1 (cosecx) = x 2. If a is some constant angle, then - sin q = sin a q = n p + (-1) n a , n Z - cos q = cos a q = 2n p..
Result
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