Nuclear Stability and Neutron/Proton Ratio
It has been found that the stability of nucleus depends upon its neutron to proton (n/p) ratio. A plot of N (the neutron number) against Z (atomic number or number of protons) show that for stable nuclides upto Z = 20, N = 20 i.e., the relationship ca..
It has been found that the stability of nucleus depends upon its neutron to proton (n/p) ratio. A plot of N (the neutron number) against Z (atomic number or number of protons) show that for stable nuclides upto Z = 20, N = 20 i.e., the relationship ca..Nuclear Stability and Neutron/Proton Ratio
It has been found that the stability of nucleus depends upon its neutron to proton (n/p) ratio. A plot of N (the neutron number) against Z (atomic number or number of protons) show that for stable nuclides upto Z = 20, N = 20 i.e., the relationship can be rep..
It has been found that the stability of nucleus depends upon its neutron to proton (n/p) ratio. A plot of N (the neutron number) against Z (atomic number or number of protons) show that for stable nuclides upto Z = 20, N = 20 i.e., the relationship can be rep..Characteristics of Electrons, Protons and Neutrons
Particle Electron Proton Neutron Symbol e p n Nature Negatively charged Positively charged Neutral Relative charge -1 +1 0 Absolute charge 1.6 x 10 -19 C 1.6 x 10 -19 C 0 Relative mass 1/1840 amu 1 amu 1 amu Absolute mass 9 x 10 ..
Characteristics of Electrons, Protons and Neutrons
Particle Electron Proton Neutron Symbol e p n Nature Negatively charged Positively charged Neutral Relative charge -1 +1 0 Absolute charge 1.6 x 10 -19 C 1.6 x 10 -19 C 0 Relative mass 1/1840 a,m.u 1 a.m.u 1 a.m.u ..
Discovery of Neutrons
Although Rutherford's model was enormously successful at explaining the scattering of alpha particles, there was a problem when the experimental data were used to calculate the mass of the nucleus. From the results of the scattering experiments, it was possible to calculate the charge on the ..
Discovery of Neutrons
Although Rutherford's model was enormously successful at explaining the scattering of alpha particles, there was a problem when the experimental data were used to calculate the mass of the nucleus. From the results of the scattering experiments, it was possible to calculate the charge on the nucle..
Stable Nuclides
Since the positive protons in the nucleus repel each other, neutrons are required to bind the nucleus together. For lighter elements, the number of protons and neutrons are approximately equal. As the number of protons increases the force required ..
Introduction
Atoms contain three fundamental particles namely electrons, protons and neutrons. Protons and neutrons constitute the nucleus whereas electrons are present in the extra nuclear region of the ato..
Unstable Nuclides
Whenever a - particle is emitted a neutron is lost and a proton gained. Therefore the neutron/proton ratio is reduced by - radiation. When an - particle is emitted the nucleus loses two protons and two neutrons. Since there were originally mo..
Solution:
Atomic number = number of protons = 11Mass number = number of protons + number of neutrons= 11 + 12 = ..
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