normal distribution to approximate the binomial distribution

When can the normal distribution be used as an approximation to the binomial distribution? => n . p = 5, n . q = 5 or n . p ≤ 5, n . q ≤ 5 or n . p > 5, n . q < 5 or n . p ≥ 5, n . q ≥ 5..

Say whether the normal distribution can be used as an approximation to the binomial distribution shown here. n = 20 and p = 0.8 => false or true or cannot be determined...

Binomial Distribution - A trial, which has only two outcomes i.e., "a success" or "a failure", is called a Bernoulli trial. Let X be the number of successes in a Bernoulli trial, then X can take 0 or 1 and P(X =1) = p = "probability of a success" P(X = 0) = 1 - p = q = "probabil..

>There are many daily life situations where n is very large and p is very small. In such situations, the Poisson distribution can be more conveniently used as an approximation to binomial distriburtion which may prove cumbersome for large values of n. This is called Po..

The graph of a normal distribution will be ________. => It has no predictable shape or Skewed left or Skewed right or Symmetric..

What percentage of area (approximately) under the normal distribution curve lies between a standard deviation of 1 and 2? => 15% or 13% or 27% or 30%..

The average price of a computer is $750. If prices of computers are approximately normally distributed with a standard deviation of $75, then what is the probability that a randomly selected computer costs more than $1000? => 3.3% or 0.33% or 0.04% or 0.4%..

Poisson Distribution - Poisson distribution is a limiting process of binomial distribution. Poisson distribution occurs when there are events which do not occur as outcomes of a definite number of outcomes. Poisson distribution is used und..

Find the area under the normal distribution curve shown in the figure. => 15.59% or 9.01% or 84.41% or 94.41%..

Five thousand candidates appeared for an examination, which carried a maximum of 100 points. These points were found to be normally distributed with mean 39.5 and standard deviation 12.5. Determine approximately the number of candidates who secured more than 60 points...