normal distribution

Find the probability P (0.65 < z < 1.84) using the standard normal distribution. => 22.49% or 24.29% or 29.42% or 70.93%..

Find the probability P ( z < 0.65) using the standard normal distribution. => 72.44% or 74.22% or 25.78% or 27.58%..

Find the z value so that 75% of the area under the standard normal distribution curve lies to the right of it. => - 0.674 or - 0.25 or 0.674 or 0.25..

Find two z values, which bound 30% of the exact middle area of a standard normal distribution. => - 0.385, + 0.385 or - 0.84, + 0.84 or - 0.4, + 0.37 or - 0.525, + 0.525..

The average length of stay in a hospital is 6.2 days. If one assumes that the number of days of hospital stay follows a normal distribution pattern with a standard deviation of 2.2 days, then what would be the minimum stay for 10% of cases? => 10 days or 7 days or 8 days or 9 da..

If the average price of a two - bedroom apartment is $225,000 in a prime location, then find their maximum and minimum prices that a builder will have to include the middle 90% of the market. Assume that the real estate price in this location is normally distributed with a stand..

The average age of media reporters worldwide is 35 years with a standard deviation of 6 years. If a media channel employs 50 media reporters, then what is the probability that their mean age lies between 34 and 37 years? Assume that the variable is normally distributed. => 87.15..

Find two z values, which bound 50% of the exact middle area of a standard normal distribution. => - 0.674, + 0.674 or - 0.674, + 4.0 or - 4.0, + 4.0 or - 4.0, + 0.674..

The mean time a student spends on a computer is 4 hours per day. Assume the standard deviation is 0.7 hour. Find the percentage of students who spend more than 4.3 hours on the computer. Assume the variable is normally distributed. => 66.56% or 88.44% or 33.36% or 16.56%..

The average age of employees in a firm is 35 years. Assume the variable is normally distributed. If the standard deviation is 3 years, then find the probability that the age of a randomly selected employee will be greater than 38 years. => 15.87% or 65.87% or 34.13% or 94.13%..