Null Matrix or Zero Matrix
A matrix of order m x n whose elements are all 0 is called a null matrix (or zero matrix) of order m x n. It is usually denoted by O or more clearly [O] m , n..
Argand diagram of the qth roots of a Complex number
All the q-th roots of z lie on a circle centred at the origin O and having radius equal to the real, positive q t h root of r. One of them has amplitude q /q and others are uniformly spaced around the circle separated from others by an angle 2p ..
Geometrical Representation of Complex Number
Geometrical representation of a Complex number, Argand diagram - Since every complex number z = x + iy is an order pair of real numbers (x, y), it can therefore be represented by a point P(x,y) in the xy plane by taking the real part along the x-axis and the imaginary ..
Geometrical representation of a Complex number, Argand diagram - Since every complex number z = x + iy is an order pair of real numbers (x, y), it can therefore be represented by a point P(x,y) in the xy plane by taking the real part along the x-axis and the imaginary ..Question 1
Question: List the elements of the following sets. Answer: i) Omit o and u from the vowels a, e, i, o, u to get {a,e,i} ii) There are exactly two such names {Karnataka, Kerala..
Question: List the elements of the following sets. Answer: i) Omit o and u from the vowels a, e, i, o, u to get {a,e,i} ii) There are exactly two such names {Karnataka, Kerala..Simplification of fractions
Remember 'BODMAS', Do the various operations in the order given below: Open brackets from within and go outwards in the order: -, (), {} and lastly []. B 1 Brackets O 2 Of D 3 Division M 4 Multiplication A 5 Addition S 6 Subtracti..
Some properties of Addition and Subtraction of Matrices
Some properties of Addition and Subtraction of Matrices - (1) A + B = B + A (Commutative property) (2) k(A + B) = kA + kB (Distributive property) (3) (A + B) + C = A + B + C (Distributive property) (4) (A + B) + C = A + (B + C) (Associative property) A + O = O + A = A where ..
Nuclear Stability and Neutron/Proton Ratio
It has been found that the stability of nucleus depends upon its neutron to proton (n/p) ratio. A plot of N (the neutron number) against Z (atomic number or number of protons) show that for stable nuclides upto Z = 20, N = 20 i.e., the relat..
It has been found that the stability of nucleus depends upon its neutron to proton (n/p) ratio. A plot of N (the neutron number) against Z (atomic number or number of protons) show that for stable nuclides upto Z = 20, N = 20 i.e., the relat..Nuclear Stability and Neutron/Proton Ratio
It has been found that the stability of nucleus depends upon its neutron to proton (n/p) ratio. A plot of N (the neutron number) against Z (atomic number or number of protons) show that for stable nuclides upto Z = 20, N = 20 i.e., the relationship ..
It has been found that the stability of nucleus depends upon its neutron to proton (n/p) ratio. A plot of N (the neutron number) against Z (atomic number or number of protons) show that for stable nuclides upto Z = 20, N = 20 i.e., the relationship ..The diameter of a proton is about 1 × 10 - 12 mm. Write this num..
The diameter of a proton is about 1 × 10 - 12 mm. Write this number in standard form. => 0.00000000001 or 0.0000000001 or 0.0000000000001 or 0.000000000001..
Structure of FeO
O 2 - form a cubic close packing. All the octahedral sites are not occupied by Fe 2 + , because a small number of Fe 2 + are replaced by Fe 3 + ions. For every three Fe 2 + replaced, there are two Fe 3 + ions and one octahedral site is vacant. Electrical neutrality i..
Result
Pages   :     1     2     3     4     5     6     7     8     9     10     11
See what our Users say :
This Tutor Vista is GREAT! loved this session, it helped me heaps.
You are an amazing tutor. So knowlegeable and patient. Very clear in explanations, 2 thumbs up -kelly
this is lawrens mom and I really like the way they work the entire problem out and show all the work. its exactly what she needs
They understand my kids needs and serve all the help which he needs in all the subjects -thank you
Looking for More Help!
