Factorisation by grouping the terms of the expression
In many situations, we come across polynomials, which may not have common factors among its terms. In such cases, we group the terms of the expression in such a way that there are common factors among the terms of the groups so formed. Let us study such exampl..
Methods of factorising polynomials
There are various methods of factorising a polynomial. They are, 1. Factorisation by dividing the expression by the HCF of the terms of the given expression. 2. Factorisation by grouping the terms of the expression. 3. Factorisation using identities. Let us study these methods one after ..
Suggested answer:
Identify the HCF of the terms of the groups. Now, observe that, (2x - 3a) is a common factor for both the groups. Therefore (2x - 3a) is one of the factors of the given expression. The other factor is identified by dividing each group by the common factor i.e. (..
Identify the HCF of the terms of the groups. Now, observe that, (2x - 3a) is a common factor for both the groups. Therefore (2x - 3a) is one of the factors of the given expression. The other factor is identified by dividing each group by the common factor i.e. (..Methods of factorising polynomials
There are various methods of factorising a polynomial. They are, Factorisation by dividing the expression by the HCF of the terms of the given expression. Factorisation by grouping the terms of the expression. Factorisation using identitie..
There are various methods of factorising a polynomial. They are, Factorisation by dividing the expression by the HCF of the terms of the given expression. Factorisation by grouping the terms of the expression. Factorisation using identitie..Suggested answer:
Step 1: The factor pairs of the last term are (7,2), (14,1), (-1,-14). Step 2: The pair of factors whose sum is equal to -15, the co- efficient of the middle term is (-1,-14). Step 3: Rewrite the expression using these factors Step 4: Group the terms and factorise. ..
Step 1: The factor pairs of the last term are (7,2), (14,1), (-1,-14). Step 2: The pair of factors whose sum is equal to -15, the co- efficient of the middle term is (-1,-14). Step 3: Rewrite the expression using these factors Step 4: Group the terms and factorise. ..Suggested answer:
Step 1: The factor pairs of the third term are ((7,4); (14,2); (28, 1). Step 2: The pair of factors whose sum is equal to the co-efficient of the middle term is 14 and 2. Step 3: Rewrite the expression using these factors Step 4: Group the terms and factorise. ..
Step 1: The factor pairs of the third term are ((7,4); (14,2); (28, 1). Step 2: The pair of factors whose sum is equal to the co-efficient of the middle term is 14 and 2. Step 3: Rewrite the expression using these factors Step 4: Group the terms and factorise. ..Suggested answer:
Step 1: Factor pairs of the last term are (9,-2); (-6,3); (-18,1);(-9,2);(6,-3); (18,-1). Step 2: The pair of factors whose sum is equal to the co-efficient of the middle term is (-6,3). Step 3: Rewrite the expression using these factors as Step 4: Group the terms and factorise. ..
Step 1: Factor pairs of the last term are (9,-2); (-6,3); (-18,1);(-9,2);(6,-3); (18,-1). Step 2: The pair of factors whose sum is equal to the co-efficient of the middle term is (-6,3). Step 3: Rewrite the expression using these factors as Step 4: Group the terms and factorise. ..Questions on Number theory
Question 1 - Question: Define an even number. Answer: A number which is divisible by 2 is called an even number..
Basic number theory question and answers
Question 1 - Question: List the elements of the following sets. Answer: i) Omit o and u from the vowels a, e, i, o, u to get {a,e,i} ii) There are exactly two such names {Karnataka, Keral..
Question 1 - Question: List the elements of the following sets. Answer: i) Omit o and u from the vowels a, e, i, o, u to get {a,e,i} ii) There are exactly two such names {Karnataka, Keral.. Result
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