Numericals
01. An object of mass 5 kg is lifted up through a distance of 2 meter. What is the work done? Solution: W = F x s Also, force acting on the object is F = mg [Newton's second law of motion] Mass of the object (m) = 5 kg Distance moved = 2m Therefore, Work done = F x s 02. How ..
01. An object of mass 5 kg is lifted up through a distance of 2 meter. What is the work done? Solution: W = F x s Also, force acting on the object is F = mg [Newton's second law of motion] Mass of the object (m) = 5 kg Distance moved = 2m Therefore, Work done = F x s 02. How ..Numericals
01. A body of mass 2kg is raised to a height of 25m. Calculate the potential energy possessed by the body. Solution: Mass of the body (m) = 2kg Height (h) = 25 m Potential energy of the body = mgh 02. A bag of rice weighs 75kg. To what height is it raised if the work done in lifting it is..
01. A body of mass 2kg is raised to a height of 25m. Calculate the potential energy possessed by the body. Solution: Mass of the body (m) = 2kg Height (h) = 25 m Potential energy of the body = mgh 02. A bag of rice weighs 75kg. To what height is it raised if the work done in lifting it is..Numericals
01. A man of mass 60 kg runs up a flight of 60 steps in 40 seconds. If each step is 20 cm high, calculate his power. Solution : Since the man runs up a flight of steps, the work done will be equal to the potential energy. Height = height of one step x number of ste..
01. A man of mass 60 kg runs up a flight of 60 steps in 40 seconds. If each step is 20 cm high, calculate his power. Solution : Since the man runs up a flight of steps, the work done will be equal to the potential energy. Height = height of one step x number of ste..General solution of a differential equation
If the solution of a differential equation of order n contains n arbitrary constants, then it is called the General solution of the differential equation..
Solution of a differential equation:
A functional relation between x and y which satisfies the given differential equation. Solution of a differential equation by the method of variables separable..
Solution
According to Dalton's Law: p CO + p CO 2 = P = 1520 mm of Hg..
According to Dalton's Law: p CO + p CO 2 = P = 1520 mm of Hg..Solution
a) The equilibrium constant for this reaction is written in terms of the partial pressures of the reactants and products. So, b) This reaction is exothermic. So, its equilibrium constant should increase with the lowering of temperature. Therefore, the value of K p at 300 K will be gre..
a) The equilibrium constant for this reaction is written in terms of the partial pressures of the reactants and products. So, b) This reaction is exothermic. So, its equilibrium constant should increase with the lowering of temperature. Therefore, the value of K p at 300 K will be gre..Solution
(a) Here, n = 1+ 1 - 1 = 1 K p = K c (RT) 1 = K c RT (b) Here, n = 2- (3+1) = -2 K p = K c (RT) - 2 (c) Here, n = 2- (1+1) = 0 K p = K c (RT) 0 = K c (d) Here, n = 2+1-2 =1 K p = K c (RT) 1 = K c RT (d) Here, n = 2- (2+1)= -1 K p = K c (RT) - 1 = K c / RT 3. At 700 K, the equilibri..
(a) Here, n = 1+ 1 - 1 = 1 K p = K c (RT) 1 = K c RT (b) Here, n = 2- (3+1) = -2 K p = K c (RT) - 2 (c) Here, n = 2- (1+1) = 0 K p = K c (RT) 0 = K c (d) Here, n = 2+1-2 =1 K p = K c (RT) 1 = K c RT (d) Here, n = 2- (2+1)= -1 K p = K c (RT) - 1 = K c / RT 3. At 700 K, the equilibri..The slope field and graphical solution of a differential equation is s..
The slope field and graphical solution of a differential equation is shown. Which of the following is that differential equation? => d y d x = 2 x or d y d x = - 2 or d y d x = 2 or d y d x = 1 2 x or d y d x = -1..
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