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Question 4
Question: Convert 1 km/h to m/s. Answer: i.e., ..
Question: Convert 1 km/h to m/s. Answer: i.e., ..Numericals
01. A man of mass 60 kg runs up a flight of 60 steps in 40 seconds. If each step is 20 cm high, calculate his power. Solution : Since the man runs up a flight of steps, the work done will be equal to the potential energy. Height = height of one step x number of ste..
01. A man of mass 60 kg runs up a flight of 60 steps in 40 seconds. If each step is 20 cm high, calculate his power. Solution : Since the man runs up a flight of steps, the work done will be equal to the potential energy. Height = height of one step x number of ste..
..Solution:
Mass of the toy car (m) = 150 g Velocity (v) = 5 m/s Momentum (p) = mv Momentum = 0.75 kg ..
Mass of the toy car (m) = 150 g Velocity (v) = 5 m/s Momentum (p) = mv Momentum = 0.75 kg ..Question 15
Question: 1 newton = ________ 1. 2. 3. 4. Answer: ..
Question: 1 newton = ________ 1. 2. 3. 4. Answer: ..Solution:
Mass (m) = 10 kg Acceleration (a) = 7m/s 2 Force = 70 kgm/s 2 Force = 7..
Mass (m) = 10 kg Acceleration (a) = 7m/s 2 Force = 70 kgm/s 2 Force = 7..Acceleration due to Gravity on Moon
The expression for acceleration due to gravity ..
The expression for acceleration due to gravity ..Force of attraction when the distance between the bodies is increased three times:
Force of Attraction Between Two Bodies of Mass m Separated by a Distance 3d That is, when the distance is doubled, the force will be reduced to 1/4 t h of the original value of force and when the distance is increased three times, the force will be reduced to 1/9 t h of the original val..
Force of Attraction Between Two Bodies of Mass m Separated by a Distance 3d That is, when the distance is doubled, the force will be reduced to 1/4 t h of the original value of force and when the distance is increased three times, the force will be reduced to 1/9 t h of the original val..Gravitational Force Between Massive Objects
Let us now calculate the force of attraction between an object of mass 50 kg and Earth. The mass of the Earth is about 6 x 10 2 4 kg. The distance between the Earth and the object is approximately 64 x 10 5 m. The force of attraction between the object and the Ear..
Let us now calculate the force of attraction between an object of mass 50 kg and Earth. The mass of the Earth is about 6 x 10 2 4 kg. The distance between the Earth and the object is approximately 64 x 10 5 m. The force of attraction between the object and the Ear..Electricity
Certain reactions take place with the help of an electric current.Example: Decomposition of acidulated water to give hydrogen and oxygen g..
Certain reactions take place with the help of an electric current.Example: Decomposition of acidulated water to give hydrogen and oxygen g..See what our Users say :
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