|
Unlimited Tutoring & Homework Help
|
|
Derivative of Sum of Two Functions
Let y = u + v, where u and v are differentiable functions of x. or (u + v)' = u' + ..
Let y = u + v, where u and v are differentiable functions of x. or (u + v)' = u' + ..Note 2:
If f and g are two continuous functions then f + g, f - g, fg are continuous function..
Example 2:
Form a differential equation by eliminatory the parameter A and B from the family of curves given by y = Ae 2 x +Be - 2 x..
Example 2:
Differentiate the following function using product rule. y = (3 sec x - 4 cosec x) (2 sin x + 5 cos..
Step 2:
Find f '(x) and examine if it is defined at every point on the open interval (a, b). If f '(x) is defined for all x (a, b), then the function is differentiabl..
Find f '(x) and examine if it is defined at every point on the open interval (a, b). If f '(x) is defined for all x (a, b), then the function is differentiabl..Step 2:
Solve f '(x) = 0 to get the critical values for f (x). Let these values be a, b, c. These are the points of maxima or minima. Arrange these values in ascending ord..
Seep 2:
Take the end points of the interva..
Step 2:
Differentiate f (x) and examine if f '(x) is defined at every point in the open interval (a, b..
Example 2:
The decay rate of radium at any point t is proportional to its mass at that time. The mass is M 0 at time t = 0. Form the differential equation and find the time when the mass will be halve..
Step 2:
Differentiate the terms containing x, y or both xy with respect to x. While differentiating the terms containing y or power of y, first..
Differentiate the terms containing x, y or both xy with respect to x. While differentiating the terms containing y or power of y, first..See what our Users say :
It's help ful session. I translate my book with him it was great time - William
This explained everything to me clearly and helped me so much and I think it has made a difference in my understanding. Its gone from small to big understanding ,I think it is a magnificent tutoring - Elizabeth
I uploaded a worksheet and I wanted to follow it with the tutor so I could learn the technical parts. It took just a few minutes to get the understanding of what I needed with the tutor. I even get through all the examples on the sheet in 25 minutes that we were focused on it.
I need tutoring from tutorvista till th end of my schooling. Tutors are not only experts they are brilliant enough to make a student like me understand the concepts of differentiation and functions.