Introduction
Arrangement and selection of objects are the central ideas of this chapter on permutations and combinations. They are widely applied in solving problems of probability, genetic engineering and life scienc..
Conclusion
We have seen the application of matrices and determinants in solving system of linear equation with three unknown variables. Matrices and determinants are also widely used in solving large system of linear equation. Some of these methods are Gauss-elimination method, Gauss-Jorda..
Introduction
Arrangement and selection of objects are the central ideas of this chapter on permutations and combinations. They are widely applied in solving problems of probability, genetic engineering and life science..
Example 1:
Using matrix method solve the following systems of linear equations 2x - y + z = -3 3x - z = - 8 2x + 6y ..
Example 2:
Using matrix method, solve the following system of linear equations x + y + z = 6 (1) x + 2y + 3z = 14 (2) x + 4y + 7z = 30 ..
Suggested answer:
= (14 - 12) - (7 - 3) + (4 - 2) = 2 - 4 + 2 = 0 The system may have infinite number of solutions or no solution. Put x = k in (1) and (2) and solve y + z = 6 - k 2y + 3z = 14 - k. Solving the above two equations, we have z = k + 2 and y = 4 - 2k When x = k, substituting t..
= (14 - 12) - (7 - 3) + (4 - 2) = 2 - 4 + 2 = 0 The system may have infinite number of solutions or no solution. Put x = k in (1) and (2) and solve y + z = 6 - k 2y + 3z = 14 - k. Solving the above two equations, we have z = k + 2 and y = 4 - 2k When x = k, substituting t..Consistency of a system of linear equation
If a system of linear equations has at least one solution, then the system is called consistent, otherwise it is called inconsistent. Solve the system of linear equations (1) by using method of elimination as studied earlier Multiplying the first equation by a 2 and the second equation ..
If a system of linear equations has at least one solution, then the system is called consistent, otherwise it is called inconsistent. Solve the system of linear equations (1) by using method of elimination as studied earlier Multiplying the first equation by a 2 and the second equation ..Matrices and Determinants Summary
[A i j ] where A i j is the co-factor of the element a i j . Adjoint of A is denoted by Adj A. Note that the concept of adj is only for square matrix. A square matrix A is said to be non-singular if |A| 0. Let A be a square matrix of order n. If there exists a square matrix B of order n, such that ..
[A i j ] where A i j is the co-factor of the element a i j . Adjoint of A is denoted by Adj A. Note that the concept of adj is only for square matrix. A square matrix A is said to be non-singular if |A| 0. Let A be a square matrix of order n. If there exists a square matrix B of order n, such that ..Question 4
Question: Prove that following lines are concurrent: 15x - 18y + 1 = 0, 12x + 10y - 3 = 0, 6x + 66y - 11 = 0. Answer: 15x - 18y + 1 = 0 ...(i) 12x + 10y - 3 = 0 ...(ii) 6x + 66y - 11 = 0 ...(iii) Solve (i) and (ii) for x and y, ..
Question: Prove that following lines are concurrent: 15x - 18y + 1 = 0, 12x + 10y - 3 = 0, 6x + 66y - 11 = 0. Answer: 15x - 18y + 1 = 0 ...(i) 12x + 10y - 3 = 0 ...(ii) 6x + 66y - 11 = 0 ...(iii) Solve (i) and (ii) for x and y, ..Concurrent Lines - Test Questions
Question 1 - Question: Find the centroid of the triangle whose sides are x + y - 1 = 0, x - 3y + 3 = 0 and x - y - 1 = 0. Answer: Let AB represent the side x + y - 1 = 0 ...(i) Let BC represent the side x - 3y + 3 = 0 ... (ii) Let CA represent the side x - y - 1 = 0 ... (iii) Solving (i) ..
Question 1 - Question: Find the centroid of the triangle whose sides are x + y - 1 = 0, x - 3y + 3 = 0 and x - y - 1 = 0. Answer: Let AB represent the side x + y - 1 = 0 ...(i) Let BC represent the side x - 3y + 3 = 0 ... (ii) Let CA represent the side x - y - 1 = 0 ... (iii) Solving (i) .. Result
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