|
Unlimited Tutoring & Homework Help
|
Trigonometrical Identities
The trigonometric ratio's are: Sine, Cosine, Tangent, Cotangent, Secant, and Cosecan..
Some Trigonometrical Identities
Some Trigonometrical Identities - 1. sin A = cos (90 o - A) 2. 3. tan A x tan (90 o - A) = 1 4. sin 2 A + cos 2 A = 1 5. 1 + tan 2 A = sec 2 A 6. 1 + cot 2 A = cosec 2 A Let us prove the above identities. Let D ABC be a right-angled triangle with B = 90 o . Let BC = a,..
Some Trigonometrical Identities - 1. sin A = cos (90 o - A) 2. 3. tan A x tan (90 o - A) = 1 4. sin 2 A + cos 2 A = 1 5. 1 + tan 2 A = sec 2 A 6. 1 + cot 2 A = cosec 2 A Let us prove the above identities. Let D ABC be a right-angled triangle with B = 90 o . Let BC = a,..Some Trigonometrical Identities
1. sin A = cos (90 o - A). 2. sin A / cos a = tan A. 3. tan A x tan (90 o - A) = 1. 4. sin 2 A + cos 2 A = 1. 5. 1 + tan 2 A = sec 2 A. 6. 1 + cot 2 A = cosec 2 A. Where 'A' is the angl..
Conditional Trigonometric Identities
Conditional Trigonometric Identities - In the previous sections many identities have been discussed. They are true for all values of the angles for which trigonometric functions are defined. In this section we prove identities, where a certain relat..
Conditional Trigonometric Identities - In the previous sections many identities have been discussed. They are true for all values of the angles for which trigonometric functions are defined. In this section we prove identities, where a certain relat..Integration using trigonometric identities
When the integrand consists of trigonometric function, we use suitable trigonometric identities to simplify the function so that it can be integrated. Few identities are given below for ready reference. (1) (2) (3) (4) (5) (7) (..
When the integrand consists of trigonometric function, we use suitable trigonometric identities to simplify the function so that it can be integrated. Few identities are given below for ready reference. (1) (2) (3) (4) (5) (7) (..Trigonometrical Identities Summary
Summary - sin A = cos (90 o - A) tan A . tan (90 o - A) = 1 sin 2 A + cos 2 A = 1 1 + tan 2 A = sec 2 A 1 + cot 2 A = cosec 2..
Summary - sin A = cos (90 o - A) tan A . tan (90 o - A) = 1 sin 2 A + cos 2 A = 1 1 + tan 2 A = sec 2 A 1 + cot 2 A = cosec 2..Trigonometric functions and it's properties
- Identical properties of circular functions and trigonometric functions. Let O be the origin. Let OA be the unit radius of the circle drawn with O as centre. Let OA trace an angle when OA takes the position OP. Then The tracing of the angle q and the arc AP = P( q ) are one and..
- Identical properties of circular functions and trigonometric functions. Let O be the origin. Let OA be the unit radius of the circle drawn with O as centre. Let OA trace an angle when OA takes the position OP. Then The tracing of the angle q and the arc AP = P( q ) are one and..Pythagorean Triplets
If a, b, c are the sides of a right angled triangle so that a 2 + b 2 = c 2 (where a, b, c N) then a, b, c form a Pythagorean Triplet. Some cases of Pythagorean Triplets are stated below. Also, the multiples of these natural numbers form Pythagorean Triplet..
If a, b, c are the sides of a right angled triangle so that a 2 + b 2 = c 2 (where a, b, c N) then a, b, c form a Pythagorean Triplet. Some cases of Pythagorean Triplets are stated below. Also, the multiples of these natural numbers form Pythagorean Triplet..Identical equations or identities
The two expressions (LHS and RHS) are always equal for any value we give to the variable. Equations that are true for any value of the variable are called identical equations or briefly an identity..
Identical equations or Identities
Now study the equations given below: a) x + 3 + x + 4 = 2x + 7 2x + 7 = 2x + 7 (By simplification) [ \ any value given to 'x' always satisfies the equation] Similarly, b) (3a + 4) + 2 (a - 1) = 5a + 2 i.e., 5a + 2 = 5a + 2 (By simplification) [ \ any value given to 'a' always satisfies the equation..
Result
Pages   :     1     2     3     4     5     6     7     8     9     10     11
See what our Users say :
I am Jessica from New York, I got excellent English tutors from Tutor Vista, who helped me lot to overcome my grammar mistakes, Thanks a lot...
Chemistry is a tough subject for me, I get a great help here along with a detailed explanation from a virtual tutor, it's really amazing - Nancy
Tutor Vista is having a great content which helps me to understand the concepts much better
I asked a Math question in the chat box in tutorvista. I was amazed to see live response from the tutor who helped me with my questions. That was great. I joined their online regular tutoring so that I can get such help anytime. - Mary

