sample problems with solution about elastic and inelastic collision in one dimension

Elastic and Inelastic Collisions in One and Two Dimensions - A Karate expert strikes a board of mass 0.14 kg and breaks it, with his fist of mass 0.70 kg. He then does the same to a 3.2 kg concrete block. The spring constant 'k' for bending are, 4.h..

A Karate expert strikes a board of mass 0.14 kg and breaks it, with his fist of mass 0.70 kg. He then does the same to a 3.2 kg concrete bloc..

If the colliding bodies do not move along the same straight line path, then the collision is said to be an oblique collision..

A body of mass m 1 is moving with a velocity along X-axis. Let it suffer elastic collision with a stationary body of mass m 2 . The distance b, between the initial line of motion and a line parallel to it through the centre of the target body is called the impact pa..

It is that elastic collision in which the colliding bodies move along the same straight line before and after the collision. Consider two bodies A and B of masses m 1 and m 2 respectively, moving along the same straight line, in the same direction. Let be the..

By law of conservation of momentum, momentum before collision is equal to momentum after collision. ..

Mass of copper oxide taken in experiment 1. = 1.375 g Mass of copper obtained = 1.098 g Mass of copper oxide produced in experiment 2 = 1.476 g Mass of copper used = 1.179 g Since the percentage of copper in the two samples of copper ..

100 g of chlorophyll contains 2.68 g of Mg 1 mole of Mg = 24 g of Mg = 6.023 x 10 2 3 atom of Mg 24 g of Mg contains, 6.023 x 10 2 3 atom of Mg =1.34 x 10 2 1 Mg atoms 13. A sample of gaseous substance weighing 0.5 g occupies a volume of 1h..

The volume of H 2 SO 4 neutralised by N/10 NaOH can be obtained as follows: N a c i d x V a c i d = N a l k a l i x V a l k a l i Therefore, Volume of N/5 H 2 SO 4 used for neutralizing NH 3 = (100 - 77) mL = 23 mL Then, Percentage of nitrogen in the sample = ..

Calculating Kinetic energy using the formula E=(1/2)mv 2 Calculating changes in gravitational potential energy near the Earth Problems involving conservation of energy in simple systems Calculating momentum as the product mv Momentum as a separately conserved quantity, d..