second grade science

Let us now calculate the force of attraction between an object of mass 50 kg and Earth. The mass of the Earth is about 6 x 10 2 4 kg. The distance between the Earth and the object is approximately 64 x 10 5 m. The force of attraction between the object and the Ear..

Certain reactions take place with the help of an electric current.Example: Decomposition of acidulated water to give hydrogen and oxygen g..

Question: SI unit of acceleration is __________. 1. 2. 3. 4. Answer: ..

Question: Identify the v- t graph representing uniform velocity. 1. 2. 3. 4. Answer: 2..

Question: What is the wavelength of sound waves produced in air by a vibrating tuning fork whose frequency is 256 Hz when the velocity of sound in air is 330 m s - 1 ? Answer: v = f 330 = 256 = = 1.3 ..

The two isotopes are..

Potential energy = mgh = mg(h - x) [Height from the ground is (h - x)] Potential energy = mgh - mgx Kinetic energy The body covers the distance x with a velocity v. We make use of the third equation of motion to obtain velocity of the body. v 2 - u 2 = 2..

W = F x S Force acting on the object is given by F = mg [Newton's second law of motion] Mass of the object (m) = 5 kg Distance moved = 2m Therefore, Work done = F x S = 98 J 02. How much work is done, when a force of 25 N displaces an object through 10 m, in the direc..

Alcohols on oxidation give aldehydes. The aldehydes on further oxidation give carboxylic acids..

Where M m and R m are the mass and radius of the moon respectively. Divide equation (1) by equation (2) We know that mass of the Earth is 100 times that of the moon and its radius is four times that of the moon. i.e., M e = 100 M m R e = 4 R..