Solution:
Mass of the bag of rice = 75 kg Work done = 4900 J Work done in lifting the bag of rice is stored in it as its potential energy. Therefore, Potential energy = mgh Height = 6.67..
Mass of the bag of rice = 75 kg Work done = 4900 J Work done in lifting the bag of rice is stored in it as its potential energy. Therefore, Potential energy = mgh Height = 6.67..Solution:
The work done in lifting coal is nothing but gravitational potential energy. Mass of coal = 10 5 kg Time = 1 hour = 60 x 60 s = 3600 s Power of the eng..
The work done in lifting coal is nothing but gravitational potential energy. Mass of coal = 10 5 kg Time = 1 hour = 60 x 60 s = 3600 s Power of the eng..Question 4
Question: Convert 1 km/h to m/s. Answer: i.e., ..
Question: Convert 1 km/h to m/s. Answer: i.e., ..Numericals
01. A man of mass 60 kg runs up a flight of 60 steps in 40 seconds. If each step is 20 cm high, calculate his power. Solution : Since the man runs up a flight of steps, the work done will be equal to the potential energy. Height = height of one step x number of ste..
01. A man of mass 60 kg runs up a flight of 60 steps in 40 seconds. If each step is 20 cm high, calculate his power. Solution : Since the man runs up a flight of steps, the work done will be equal to the potential energy. Height = height of one step x number of ste..Solution:
Mass of the toy car (m) = 150 g Velocity (v) = 5 m/s Momentum (p) = mv Momentum = 0.75 kg ..
Mass of the toy car (m) = 150 g Velocity (v) = 5 m/s Momentum (p) = mv Momentum = 0.75 kg ..Question 15
Question: 1 newton = ________ 1. 2. 3. 4. Answer: 2..
Question: 1 newton = ________ 1. 2. 3. 4. Answer: 2..Solution:
Mass (m) = 10 kg Acceleration (a) = 7m/s 2 Force = 70 kgm/s 2 Force = 7..
Mass (m) = 10 kg Acceleration (a) = 7m/s 2 Force = 70 kgm/s 2 Force = 7..Acceleration due to Gravity on Moon
Where M m and R m are the mass and radius of the moon respectively. Divide equation (1) by equation (2) We know that mass of the Earth is 100 times that of the moon and its radius is four times that of the moon. i.e., M e = 100 M m R e = 4 R..
Where M m and R m are the mass and radius of the moon respectively. Divide equation (1) by equation (2) We know that mass of the Earth is 100 times that of the moon and its radius is four times that of the moon. i.e., M e = 100 M m R e = 4 R..Force of attraction when the distance between the bodies is increased three times:
Force of Attraction Between Two Bodies of Mass m Separated by a Distance 3d That is, when the distance is doubled, the force will be reduced to 1/4 t h of the original value of force and when the distance is increased three times, the force will be reduced to 1/9 t h of the original val..
Force of Attraction Between Two Bodies of Mass m Separated by a Distance 3d That is, when the distance is doubled, the force will be reduced to 1/4 t h of the original value of force and when the distance is increased three times, the force will be reduced to 1/9 t h of the original val.. Result
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