If sin B = - 15/ 17 and the terminal side of ∠B is in quadrant..
If sin B = - 15 / 17 and the terminal side of ∠ B is in quadrant IV, then find the value of tan B and cos B. => 15 / 8 , 8 / 17 or - 15 / 8 , - 8 / 17 or - 8 / 15 , - 15 / 17 or - 15 / 8 , 8 / 17..
Derivative of tan x
Let f(x) = tan x. Then, we have ..
Let f(x) = tan x. Then, we have ..If sin A = 117,0° < ∠A < 90° and tan B = 13,0° &..
If sin A = 1 1 7 , 0° < ∠ A < 90° and tan B = 1 3 , 0° < ∠ B < 90°, then find the value of tan (A + B) . => 1 / 11 or 7 / 11 or 7 / 13 or 1 / 13..
1 - (sin A ⋅ sec Atan A) = ___________.
1 - ( sin A ⋅ sec A tan A ) = ___________. => sec 2 A or 1 - tan 2 A or 1 or 0..
Solve sin θ = - 32 and tan θ = 3 where 0° ≤ x≤ 3..
Solve sin θ = - 3 2 and tan θ = 3 where 0° ≤ x ≤ 360° . => 240° or 300° or 60° or 120°..
Find dydx, if 8sin2x + 3tan2y = 5x.
Find d y d x , if 8sin 2 x + 3tan 2 y = 5 x . => ( 5 - 8 sin 2 x ) ( 6 tan y sec ² y ) or ( 5 + 8 sin 2 x ) ( 6 tan y sec ² y ) or ( 5 + 8 sin 2 x ) ( sec ² y ) or none of the above..
If y = tan-1(cos 8x1 + sin 8x), then y′ =
If y = tan -1 ( cos 8 x 1 + sin 8 x ), then y′ = => π / 4 - 8 x or π / 4 - 4 or - 4 or π / 4 - 4 x..
Find the value of csc θ and cot θ if tan θ = - 4/..
Find the value of csc θ and cot θ if tan θ = - 4 / 3 and sin θ > 0. => 5 / 3 , 5 / 4 or - 5 / 4 , - 3 / 4 or - 5 / 4 , 3 / 4 or 5 / 4 , - 3 / 4..
Evaluate: limx→0 [tan 9xsin 10x-sin 9x]
Evaluate: lim x → 0 [ tan 9 x sin 1 0 x - sin 9 x ] => - 9 or ∞ or 0 or 9 / 19 or 9..
Which is greater: tan 1° or tan 1 radian?
Which is greater: tan 1° or tan 1 radian? => tan 1° or cannot be determined or both are equal or tan 1 radian..
See what our Users say :
Tutors are AMAZING, and They helped me understand every single part of the problem and because of the way they explained everything, i had no questions to ask. It was a learning experience to remember. :)
Thanks for all your help. Tutor is helping me realize how important symbols are in algebra, that makes a difference - Carter
Good teaching skills, an amazing tutoring, would recommend it to everyone - Maadai
Great sessions, learned a lot and got lots in and techniqul problem systm is showing me out of the session when i am not ,This is Awesome - Haley