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Initial Value Problem
Suppose the function Then \ f (x) = x 2 + 2x + 1 is a particular solution of the differential equation y''= 2. For the functi..
Suppose the function Then \ f (x) = x 2 + 2x + 1 is a particular solution of the differential equation y''= 2. For the functi..Solutions
Solutions - Solution is defined as a homogeneous mixture of two or more chemical substances. The state of matter of a solution may be solid, liquid or gaseous. For example, common salt in water (liquid solution), air (gaseous solution), alloys (soli..
Solutions
Solution is defined as a homogeneous mixture of two or more chemical substances. The state of matter of a solution may be solid, liquid or gaseou..
SOLUTIONS
Definitions of solute and solvent The dissolving process as a result of random molecular motion Temperature, pressure, and surface area - their affect the dissolving process Concentration of a solute in terms of grams per liter, molarity, parts per million and percent co..
SOLUTIONS
Definitions of solute and solvent The dissolving process as a result of random molecular motion Temperature, pressure, and surface area - their affect the dissolving process Concentration of a solute in terms of grams per liter, molarity, parts per million and percent co..
Solute
is a substance that can dissolve in a solvent, to form a solution. Examples: Salt, sugar, et..
Solutions
A Solution is a homogeneous mixture of two or more chemically non-reacting substances called components. The composition of the components can be varied with in certain limit..
Solution
(a) 38% solution, means 38 g of HCl in 100 g of solution. Then, Mass of the solution= 100 g Molar mass of HCl = 36.5 g mol - 1 (b) The molarity of conc. HCl sample = 12.38 mol/L Molarity of HCl solution to be prepared = 0.10 mol/L Volume of HCl ..
(a) 38% solution, means 38 g of HCl in 100 g of solution. Then, Mass of the solution= 100 g Molar mass of HCl = 36.5 g mol - 1 (b) The molarity of conc. HCl sample = 12.38 mol/L Molarity of HCl solution to be prepared = 0.10 mol/L Volume of HCl ..Solution
Heat capacity of solution = Mass of solution x Specific heat capacity Total mass of solution = 100 + 100 = 200 ml Heat capacity of solution = 200 x 4.2 = 840 JK - 1 Heat change in the reaction = Heat capacity x Rise in temperature = (840 JK - 1 ) (298.006..
Heat capacity of solution = Mass of solution x Specific heat capacity Total mass of solution = 100 + 100 = 200 ml Heat capacity of solution = 200 x 4.2 = 840 JK - 1 Heat change in the reaction = Heat capacity x Rise in temperature = (840 JK - 1 ) (298.006.. Result
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