Substitution Method
The solution is x = -9 and y = -2. Solve 43x + 31y = 241 (i) 31x + 43y = 277 (ii) By adding (i) and (ii), we get 74x + 74y = 518 x + y = 7 (iii) By subtracting (ii) from (i) 12..
The solution is x = -9 and y = -2. Solve 43x + 31y = 241 (i) 31x + 43y = 277 (ii) By adding (i) and (ii), we get 74x + 74y = 518 x + y = 7 (iii) By subtracting (ii) from (i) 12..Substitution Method-Simultaneous EquationsThe solution is x = -9 and y = -2. Solve 43x + 31y = 241 (i) 31x + 43y = 277 (ii) By adding (i) and (ii), we get 74x + 74y = 518 x + y = 7 (iii) By subtracting (ii) from (i) 12..
The solution is x = -9 and y = -2. Solve 43x + 31y = 241 (i) 31x + 43y = 277 (ii) By adding (i) and (ii), we get 74x + 74y = 518 x + y = 7 (iii) By subtracting (ii) from (i) 12..Question 7
Question: Find the equation of the bisectors of the angles between the lines 3x - 4y = 8 and 4x + 3y = 10. Answer: The given equation of lines is rewritten with positive constant. i.e., -3x..
Question: Find the equation of the bisectors of the angles between the lines 3x - 4y = 8 and 4x + 3y = 10. Answer: The given equation of lines is rewritten with positive constant. i.e., -3x..Question 7
Question: Solve the following equation: Answer: 5(3x+5) = 2(2x-1) (by cross-multiplication) 15x-4x = -2-25 11x = -27 ..
Question: Solve the following equation: Answer: 5(3x+5) = 2(2x-1) (by cross-multiplication) 15x-4x = -2-25 11x = -27 ..Solve: 63x+93x+18 = 3
Solve: 63x+9 3x+18 = 3 => 6 7 or 5 6 or 4 5 or None of the above..
Solve the system of equations by substitution: x - 3y + z = 0, 2y + 3z..
Solve the system of equations by substitution: x - 3 y + z = 0, 2 y + 3 z = 1, and z = - 2 => x = 25 2 , y = - 7 2 , z = -2 or x = 25 2 , y = 7 2 , z = -2 or x..
Suggested answer:
= (14 - 12) - (7 - 3) + (4 - 2) = 2 - 4 + 2 = 0 The system may have infinite number of solutions or no solution. Put x = k in (1) and (2) and solve y + z = 6 - k 2y + 3z = 14 - k. Solving the ..
= (14 - 12) - (7 - 3) + (4 - 2) = 2 - 4 + 2 = 0 The system may have infinite number of solutions or no solution. Put x = k in (1) and (2) and solve y + z = 6 - k 2y + 3z = 14 - k. Solving the ..Question 2
Question: Show that the lines 3x - y - 6 = 0, 4x - y - 7 = 0 and 2x - y - 5 = 0 are concurrent. Answer: Given lines are Solving (i) and (ii) for x and y, we get Th..
Question: Show that the lines 3x - y - 6 = 0, 4x - y - 7 = 0 and 2x - y - 5 = 0 are concurrent. Answer: Given lines are Solving (i) and (ii) for x and y, we get Th..Simultaneous Equations-Method of Elimination
Method of Elimination - Solve: 3x - 4y = 20 (i) 5x + 6y = 8 (ii) Multiply (i) by 3 and (ii) by 2: Adding the two, 19x = 76 Substituting x = 4 in (ii), we get 5(4) + 6..
Method of Elimination - Solve: 3x - 4y = 20 (i) 5x + 6y = 8 (ii) Multiply (i) by 3 and (ii) by 2: Adding the two, 19x = 76 Substituting x = 4 in (ii), we get 5(4) + 6..Example:
Solve the system of linear equations. x +2y + 3z = 6 2x + 4y + z = 7 3x + 2y + 9z = 14 using Cramer's rul..
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