solve by elimination method

Solve: 3x - 4y = 20 (i) 5x + 6y = 8 (ii) Multiply (i) by 3 and (ii) by 2: Adding the two, 19x = 76 Substituting x = 4 in (ii), we get 5(4) + 6y = 8 6y = 8 - 20 6y = -12 y = -2 The solution is x = 4 and y = -2..

Method of Elimination - Solve: 3x - 4y = 20 (i) 5x + 6y = 8 (ii) Multiply (i) by 3 and (ii) by 2: Adding the two, 19x = 76 Substituting x = 4 in (ii), we get 5(4) + 6y = 8 6y = 8 - 20 6y = -12 y = ..

Use the elimination method to solve the linear system. 6 x + 5 y = 49 5 y = 41 - 4 x => (4, 5) or (- 4, - 5) or (- 4, 5) or (4, - 5)..

Solve the system of equations using Gaussian elimination method. x = 10 - 3 z y = 4 - 2 x 4 z = 5 y + 2 => (4, - 4, 2) or (1, - 2, 3) or (1, 2, 3) or (0, 4, 6)..

Use Elimination method to solve the system. x + z = 5 y + z = 0 x - 2 y = - 6 => (16, 11, 11) or (- 11, 11, 6) or (6, 11, - 11) or (16, 11, - 11)..

Solve the system of equations by Gauss elimination method: x + 2 y = 4, 3 x + 4 y = 5, and 2 x + 3 y = 4 => x = 2, y = -5, z = 0 or x = 6, y = -7, z = 1 or x = -3, y = 6, z = 0 or No solution..

Solve the system using Elimination method: x 2 1 + y 2 0 = 67 x 4 - z 2 1 = - 1 5 x - y 4 = 105 => (84, 1420, 420) or (84, 1260, 462) or (88, 1260, 420) or (88, 1420, 462)..

Solve the system using elimination method: x 1 3 + y 1 2 = 15 x 2 - z 1 3 = - 1 3 x - y 4 = 39 => (28, 156, 156) or (26, 156, 182) or (28, 204, 182) or (26, 204, 156)..

Graphical Method of Solution of a Linear Programming Problem - So far we have learnt how to construct a mathematical model for a linear programming problem. If we can find the values of the decision variables x 1 , x 2 , x 3 , ..... x n , which can optimise (maximize or minimize) the obje..

Solve the system using Elimination method. w + x - y - z = 0 - 2 w + x + 4 y + 3 z = 6 3 w - x + 2 z = 4 w + 5 y - 5 z = 1 => (1, 1, 1, 1) or (1, 1, 1, 0) or (0, - 1, 1, 4) or (1, - 1, 0, - 1)..